我的理解是，當(dāng)我創(chuàng)建一個(gè)對(duì)象時(shí)，foo := &bar{}我正在為該對(duì)象分配新內(nèi)存。那么，當(dāng)我嘗試在 goroutine 中替換 *foo 時(shí)，為什么它沒有獲得新的指針地址？package mainimport (    "fmt"    "math/rand"    "sync"    "time")type pointerToObjects struct {    objs *objects}type objects struct {    sliceOfObject []*object}type object struct {    number  int    boolean bool}func main() {    p := &pointerToObjects{objs: newObjects()}    mu := &sync.Mutex{}    for _, o := range p.objs.sliceOfObject {        o.setBool(true)    }    // goroutine 1    go func() {        ticker := time.NewTicker(time.Second)        defer ticker.Stop()        for range ticker.C {            mu.Lock()            fmt.Printf("objects pointer: %v\n", &p.objs)            for i, o := range p.objs.sliceOfObject {                fmt.Printf("i: %d p: %v n: %d b: %t\n", i, &o, o.number, o.boolean)            }            fmt.Print("---\n")            mu.Unlock()        }    }()    // goroutine 2    go func() {        ticker := time.NewTicker(time.Second * 2)        defer ticker.Stop()        for range ticker.C {            newObjects := &objects{sliceOfObject: newSliceOfObject()}            mu.Lock()            p.objs = newObjects            mu.Unlock()            fmt.Printf("replaced: %v <-- %v \n", &p.objs, &newObjects)        }    }()    // let the goroutines run for 10 seconds    time.Sleep(time.Second * 10)}func newObjects() *objects {    objs := &objects{}    objs.sliceOfObject = newSliceOfObject()    return objs}func newSliceOfObject() []*object {    var sliceObjs []*object    for i := 0; i < 3; i++ {        sliceObjs = append(sliceObjs, newObject())    }    return sliceObjs}func newObject() *object {    return &object{number: rand.Int()}}func (obj *object) setBool(b bool) {    obj.boolean = b}運(yùn)行時(shí)，值會(huì)按我的預(yù)期更新，但指向的指針p保持objects不變。我希望它會(huì)在我打電話時(shí)更新*p.objs = *newObjects這是編譯器的把戲嗎？如何獲取“對(duì)象指針”以更新到新位置？我需要使用更明確的指針嗎？編輯：修復(fù)了比賽條件并嘗試分配p.objs = newObjects但沒有成功。