簡(jiǎn)單的游戲問(wèn)題第1部分我正在編寫(xiě)一個(gè)簡(jiǎn)單的 JavaScript 游戲（簡(jiǎn)單易玩，不一定要為我編寫(xiě)代碼）。我需要弄清楚龍是否距離玩家 2 步（或更少）。龍可以對(duì)角移動(dòng)。所以在我的形象中，D1不是兩步之遙，但是，D2是兩步之遙。我想我讓這比實(shí)際上更難。var player = {    x: 4,    y: 2}var dragon1 = {    x: 1,    y: 3}var dragon2 = {    x: 6,    y: 3}function isTwoMovesAway(player, dragon){    // I JUST DON'T KNOW HOW TO MATHEMATICALLY    // FIGURE THIS OUT because sometimes I end    // end up with a negative number.        xDiff = player.x - dragon.x;    yDiff = player.y - dragon.y;    numSquaresAway = [ insert your magic here ];    return (numSquaresAway<=2) ? true: false; }第2部分這個(gè)問(wèn)題的第二部分是，如果龍?jiān)谧汾s玩家，我如何確定他應(yīng)該移動(dòng)到哪個(gè)方格？我希望龍走最短的路線(xiàn)。function moveDragon(){    pX = player.x;    pY = player.y;    dX = dragon1.x;    dY = dragon1.y;    // In this case, I would expect the Dragon to move    // to either 2,2 or 2,3    // Is this just a matter of adding to X ??    Dragon1.x = [ YOUR MATH HERE ];    Dragon1.y = [ YOUR MATH HERE ];}感謝您的關(guān)注。任何意見(jiàn)，將不勝感激。