我有一個(gè) LazyInitializationException 問題，我不知道如何解決它。for (Long id : employeeIds) { List<ProjectEmployee> projectEmployeeList = projectEmployeeService.findProjectEmployeesWithinDates(id, startDate, endDate); // if no data, then continue with next employee if (projectEmployeeList.isEmpty()) { continue; } gridCreated = true; Employee employee = projectEmployeeList.get(0).getEmployee(); Label titleLabel = new Label(employee.getPerson().getSurname() + " " + employee.getPerson().getName() + " [" + employee.getRole().getHumanizedRole() + "]"); titleLabel.setStyleName("header-bold"); ProjectEmployeePanel projectEmployeePanel = new ProjectEmployeePanel(id, startDate, endDate); gridPanelsLayout.addComponents(titleLabel, projectEmployeePanel); }在問題出現(xiàn)之前，當(dāng)我打電話給 .getperson=null 但我修復(fù)了調(diào)用 findProjectEmployeesWithinDates 要求那里接人的問題。但是當(dāng)我調(diào)用“findProjectEmployeesWithinDates”時(shí)出現(xiàn)異常。代碼 findProjectEmployeesWithinDates： public List<ProjectEmployee> findProjectEmployeesWithinDates(Long employeeId, LocalDate startDate, LocalDate endDate) { List<Long> list = new ArrayList<>(); list.add(employeeId); List<ProjectEmployee> listProjectEmployees = projectEmployeeRepository.findProjectEmployeesWithinDates(list, LocaleUtils.getDateFromLocalDate(startDate, LocaleUtils.APPLICATION_DEFAULT_ZONE_ID), LocaleUtils.getDateFromLocalDate(endDate, LocaleUtils.APPLICATION_DEFAULT_ZONE_ID)); for (ProjectEmployee pe : listProjectEmployees) { Hibernate.initialize(pe.getEmployee()); Hibernate.initialize(pe.getEmployee().getPerson()); } return listProjectEmployees;}所以使用 debbug 我看到了： Hibernate.initialize(pe.getEmployee()); ----line 105Hibernate.initialize(pe.getEmployee().getPerson()); ---line 106它位于 findProjectEmployeesWithinDates 中 for 循環(huán)的第一行，但不在第二行，這就是發(fā)生異常的地方。
2 回答
Smart貓小萌
TA貢獻(xiàn)1911條經(jīng)驗(yàn) 獲得超7個(gè)贊
我會(huì)推薦以下方法之一：
1）在您的存儲(chǔ)庫方法findProjectEmployeesWithinDates中，您可以執(zhí)行
for (ProjectEmployee pe : listProjectEmployees)
{
pe.getEmployee().getPerson();
}
所以它會(huì)在會(huì)話打開時(shí)初始化對(duì)象
2）您可以使用查詢獲取數(shù)據(jù)
SELECT * FROM ProjectEmployee pe JOIN FETCH pe.employee e JOIN FETCH e.person
這樣，Hibernates 將自動(dòng)使用員工和人員對(duì)象填充執(zhí)行結(jié)果
慕雪6442864
TA貢獻(xiàn)1812條經(jīng)驗(yàn) 獲得超5個(gè)贊
當(dāng)您調(diào)用 projectEmployeeRepository.findProjectEmployeesWithinDates 方法時(shí)，它會(huì)返回 List。此時(shí)您的休眠會(huì)話已經(jīng)關(guān)閉。
因此，當(dāng)讀取 ProjectEmployee 對(duì)象時(shí)，您只能訪問那些特定于對(duì)象的變量而不是特定于對(duì)象的子對(duì)象，因?yàn)槟跒樽訉?duì)象使用延遲初始化。
因此，解決方法是保持您的休眠會(huì)話打開或使用急切獲取或使用包裝類對(duì)象將值從 ProjectEmployee 類傳輸?shù)?projectEmployeeRepository.findProjectEmployeesWithinDates 方法中的 ProjectEmployeeWrapper，然后返回 ProjectEmployeeWrapper 對(duì)象的列表
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