使用 lxml 庫，擁有這個 doc xml 文件，我想剝離一些標(biāo)簽并重命名它們：doc.xml<html> <body> <h5>Fruits</h5> <div>This is some <span attr="foo">Text</span>.</div> <div>Some <span>more</span> text.</div> <h5>Vegetables</h5> <div>Yet another line <span attr="bar">of</span> text.</div> <div>This span will get <span attr="foo">removed</span> as well.</div> <div>Nested elements <span attr="foo">will <b>be</b> left</span> alone.</div> <div>Unless <span attr="foo">they <span attr="foo">also</span> match</span>.</div> </body></html>而不是 html,body 將所有內(nèi)容包裝在“p tag”中，而不是讓 h5 和每個 div 使用 lxml 將所有內(nèi)容作為示例包裝如下：我的問題是如何從一種格式以下面的格式包裝所有內(nèi)容？<p><h5 title='Fruits'> <div>This is some <span attr='foo'>Test</span>.</div><div>Some<span>more</span>text.</div></h5><h5 title='Vegetables'><div>Yet another line <span attr='bar'>of</span>text.</div>....</h5></p>使用 lxml，剝離標(biāo)簽：tree = etree.tostring(doc.xml)tree1 = lxml.html.fromstring(tree)etree.strip_tags(tree1, 'body')有人對此有任何想法嗎？
2 回答
皈依舞
TA貢獻(xiàn)1851條經(jīng)驗 獲得超3個贊
創(chuàng)建一個只有標(biāo)簽的新文檔。
<p>迭代
<body>原始文檔中標(biāo)記的后代。如果遇到
<h5>標(biāo)簽；將<h5>標(biāo)簽添加到<p>標(biāo)簽并將后續(xù)標(biāo)簽作為后代添加到它（
<h5>）將標(biāo)簽從原始文檔添加到新文檔 - 作為其
<p>標(biāo)簽 的后代
至尊寶的傳說
TA貢獻(xiàn)1789條經(jīng)驗 獲得超10個贊
這是使用 lxml 的 xslt 解決方案。它將處理卸載到 libxml。我在轉(zhuǎn)換樣式表中添加了注釋：
from lxml import etree
xsl = etree.XML('''
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" />
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<p>
<xsl:apply-templates select="html/body"/>
</p>
</xsl:template>
<!-- match body, but do not add content; this excludes /html/body elements -->
<xsl:template match="body">
<xsl:apply-templates />
</xsl:template>
<xsl:template match="h5">
<!-- record the current h5 title -->
<xsl:variable name="title" select="."/>
<h5>
<xsl:attribute name="title">
<xsl:value-of select="$title" />
</xsl:attribute>
<xsl:for-each select="following-sibling::div[preceding-sibling::h5[1] = $title]">
<!-- deep copy of each consecutive div following the current h5 element -->
<xsl:copy-of select="." />
</xsl:for-each>
</h5>
</xsl:template>
<!-- match div, but do not output anything since we are copying it into the new h5 element -->
<xsl:template match="div" />
</xsl:stylesheet>
''')
transform = etree.XSLT(xsl)
with open("doc.xml") as f:
print(transform(etree.parse(f)), end='')
如果樣式表存儲在文件名 doc.xsl 中，則可以使用 libxml 實用程序 xsltproc 獲得相同的結(jié)果：
xsltproc doc.xsl doc.xml
結(jié)果：
<?xml version="1.0"?>
<p>
<h5 title="Fruits">
<div>This is some <span attr="foo">Text</span>.</div>
<div>Some <span>more</span> text.</div>
</h5>
<h5 title="Vegetables">
<div>Yet another line <span attr="bar">of</span> text.</div>
<div>This span will get <span attr="foo">removed</span> as well.</div>
<div>Nested elements <span attr="foo">will <b>be</b> left</span> alone.</div>
<div>Unless <span attr="foo">they <span attr="foo">also</span> match</span>.</div>
</h5>
</p>
添加回答
舉報
0/150
提交
取消