replace this option.text = data[i].styleName;let keys=Object.keys(data[i])    with option.text = data[i][keys[0]].styleName我的問題是我需要從一個數(shù)組（tFields）中讀取表中的名稱和列數(shù)，以及從第二個數(shù)組（tRecords）中讀取元素數(shù)據(jù)。我已經(jīng)實現(xiàn)了列的讀取和創(chuàng)建，請大家?guī)兔蛘吒嬖V我創(chuàng)建列表的問題出在哪里。這是代碼：function buildColumns() {var rc = vConnection.recCountvar fc = vConnection.fldCountfor(var i = 0; i < fc; ++i){    var str = 'import QtQuick 2.1; import QtQuick.Controls 1.0; import QtQuick.Layouts 1.0; TableViewColumn{ id: idColumn; role: '    str += '"' + vConnection.tFields[i] + '"' + '; title: ' + '"' + vConnection.tFields[i] + '"' +  '; width: ' + (tblPage.width / vConnection.fldCount) +'; Component.onCompleted: console.log("YEY");}'    tbl.addColumn(Qt.createQmlObject(str, tbl))}for(var j = 0; j < rc; ++j){    var str2 = 'import QtQuick 2.12; import QtQuick.Window 2.12; import QtQuick.Controls 2.4; import QtQuick.Controls.Imagine 2.3; import QtQuick.Templates 2.5; import QtQuick.Controls 1.4; ListElement { id: idColumn; '    for(var f = 0; f < fc; ++f)    {        str2 += vConnection.tFields[f] + ': "' + vConnection.tRecords[f + rc] + '"; '    }    str2 += '}'    Qt.createQmlObject(str2, lmTable)}}Component.onCompleted: {    buildColumns();}TableView {id: tblanchors.fill: parentmodel: ListModel {    id: lmTable}}}