我正在嘗試完成一個挑戰(zhàn)并且我卡住了：我有一個大電影數(shù)組，其中有一個屬性類型名稱，這是另一個數(shù)組。我想通過從存儲在數(shù)組selectedGenres中的復(fù)選框中檢查其流派名稱來過濾這部電影 我的困難出現(xiàn)在這里，當(dāng)我必須檢查每個流派名稱 數(shù)組與selectedGenres中的所有元素時。任務(wù)是，如果selectedGenres中有多個流派，則僅顯示具有所有這些選定流派的電影，而不僅僅是其中一個。代碼：const movies = [ {title:"movie 1",genreName:["Action", "Drama"]},{title:"movie 2",genreName:["Action", "Fantasy", "Adventure"]},{title:"movie 3",genreName:["Action", "Fantasy", "Science Fiction"]},{title:"movie 4",genreName:["Action", "Drama", "Thriller"]}]const selectedGenres = ["Action","Drama"];  //based on this selection, only movie1 and movie4 should be in the filteredMovies variable.const filteredMovies = movies.filter(movie => { //loop through each movie        movie.genreName.filter(genre => { // loop through each item in genreName array          return selectedGenres.forEach(name => { // loop through each item in selectedGenres array            return name.indexOf(genre) > -1;          });        });      });