假設(shè)我有這樣的 JSON 消息：{ "aaaa": 14, "bbbb": "", "cccc": { "c1": 121, "needed": [ { "_c21": 22.25972, "_c22": { "needed1": "123", "needed2": "test" } }, { "_c21": 22.25972, "_c22": { "needed1": "123", "needed2": "test" } }, { "_c21": 22.25972, "_c22": { "needed1": "123", "needed2": "test" } } ] }}我怎樣才能把它轉(zhuǎn)換成類似的東西：{ "needed": [{ "needed1": "123", "needed2": "test" }, { "needed1": "123", "needed2": "test" }, { "needed1": "123", "needed2": "test" } ]}在這種情況下，我認為需要進行迭代來檢索needed1并且needed2僅檢索組件。我還想知道 Golang 處理 nil 和 empty 的最佳做法是什么？（和Java一樣，在處理數(shù)據(jù)之前，建議先用if條件檢查每個鍵）
1 回答
慕仙森
TA貢獻1827條經(jīng)驗 獲得超8個贊
下面的代碼應(yīng)該給你你需要的東西：
package main
import (
"encoding/json"
"fmt"
)
var input = `{
"aaaa": 142,
"bbbb": "",
"cccc": {
"c1": 121,
"needed": [
{
"_c21": 22.25972,
"_c22": {
"needed1": "123",
"needed2": "test"
}
},
{
"_c21": 22.25972,
"_c22": {
"needed1": "123",
"needed2": "test"
}
},
{
"_c21": 22.25972,
"_c22": {
"needed1": "123",
"needed2": "test"
}
}
]
}
}`
type Json struct {
Cccc struct {
NeededList []struct {
C22 needed `json:"_c22"`
} `json:"needed"`
}`json:"cccc"`
}
type needed struct {
Needed1 string `json:"needed1"`
Needed2 string `json:"needed2"`
}
func main() {
j := &Json{}
json.Unmarshal([]byte(input), j)
result := make([]needed, 0)
for _, n := range j.Cccc.NeededList {
result = append(result, n.C22)
}
out, _ := json.Marshal(result)
fmt.Println(string(out))
}
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