我必須編寫一個程序，首先請求 0 < N < 20 范圍內(nèi)的整數(shù)。超出此范圍的數(shù)字將被拒絕并發(fā)出新請求。輸出從 1 開始到 N 結(jié)束的數(shù)字序列的總和。我已經(jīng)得到了大部分代碼，但我不能不斷地要求用戶輸入，直到輸入滿足要求。我嘗試在第 11 行使用“return”，但是在獲得另一個輸入后它不會返回循環(huán)。我現(xiàn)在該怎么辦？import java.util.*;class ExamTesterNine{ public static void main(String args[]){ Scanner kbReader= new Scanner(System.in); int num=kbReader.nextInt(); System.out.println("Enter an integer smaller than 20 and larger than 0"); int result; int sum=0; if (!(num>0&&num<20)){ return; }else{ for(int i=1; i<=num; i++) sum=sum+i; int [] number= new int [num]; for (int a=0; a<(number.length-1); a++ ){ number[a]=a+1; System.out.print(number[a]+"+");} System.out.print(num+"="+sum); } }}
3 回答
慕尼黑的夜晚無繁華
TA貢獻1864條經(jīng)驗 獲得超6個贊
IT 應(yīng)該很容易使用do-while. 我現(xiàn)在不在我的編譯器上，但是如果你使用掃描儀，你應(yīng)該在你的代碼中添加這個
import java.util.*;
class ExamTesterNine{
public static void main(String args[]){
Scanner kbReader= new Scanner(System.in);
int num = 0;
System.out.println("Enter an integer smaller than 20 and larger than 0");
do{
num=kbReader.nextInt();
} while(num<0 && num <20);
int result;
int sum=0;
for(int i=1; i<=num; i++)
sum=sum+i;
int [] number= new int [num];
for (int a=0; a<(number.length-1); a++ ){
number[a]=a+1;
System.out.print(number[a]+"+");}
System.out.print(num+"="+sum);
}
}
}
如果不能，請告訴我，我可以快速進入編譯器，但這do-while是您的解決方案。
臨摹微笑
TA貢獻1982條經(jīng)驗 獲得超2個贊
您將需要一個while循環(huán)，因為您不知道會輸入多少次錯誤輸入
while (true) {
System.out.println("Enter an integer smaller than 20 and larger than 0");
int num=kbReader.nextInt(); // get input
// test
if (goodInput (num)) {
break;
}
}
倚天杖
TA貢獻1828條經(jīng)驗 獲得超3個贊
import java.util.*;
class ExamTesterNine{
static int num;
public static void readInput() {
System.out.println("Enter an integer smaller than 20 and larger than 0");
Scanner kbReader= new Scanner(System.in);
num=kbReader.nextInt();
if (!(num>0&&num<20)){
ExamTesterNine.readInput();
}else {
calculate(num);
}
}
public static void calculate(int sum) {
for(int i=1; i<=num; i++)
sum=sum+i;
int [] number= new int [num];
for (int a=0; a<(number.length-1); a++ ){
number[a]=a+1;
System.out.print(number[a]+"+");}
System.out.print(num+"="+sum);
}
public static void main(String args[]){
int result;
int sum=0;
ExamTesterNine.readInput();
}
}
Are you expecting this?
Out put:Enter an integer smaller than 20 and larger than 0
23
Enter an integer smaller than 20 and larger than 0
34
Enter an integer smaller than 20 and larger than 0
56
Enter an integer smaller than 20 and larger than 0
45
Enter an integer smaller than 20 and larger than 0
15
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15=135
添加回答
舉報
0/150
提交
取消