我正在嘗試按最高值匹配進(jìn)行規(guī)則過濾。我有一個(gè)包含多個(gè)產(chǎn)品的銷售，我必須對(duì)每個(gè)產(chǎn)品應(yīng)用不同的規(guī)則。獲得此結(jié)果的最佳方法是什么？List<Rule> rules = listOfRules();String system = "MySystem1";Map<Product, Rule> mapOfProductRule = new HashMap<Product, Rule>();sale.getProducts().forEach(product -> { int points = 0; Rule matchedRule = null; for (Rule rule : rules) { if (system == rule.getSystem()) { int countMatchs = 0; if (sale.getValue1() == rule.getValue1()) countMatchs++; if (sale.getValue2() == rule.getValue2()) countMatchs++; if (product.getPvalue1() == rule.getPvalue1()) countMatchs++; if (product.getPvalue2() == rule.getPvalue2()) countMatchs++; if (countMatchs!= 0 && points < countMatchs) { points = countMatchs; matchedRule = rule; } } } mapOfProductRule.put(product, matchedRule);});return mapOfProductRule;
1 回答
德瑪西亞99
TA貢獻(xiàn)1770條經(jīng)驗(yàn) 獲得超3個(gè)贊
首先，我會(huì)將所有 4 if.. 移動(dòng)到Rule類中的一個(gè)方法中
public int getScore(Sale sale, Product product) {
int count = 0;
if (this.getValue1() == sale.getValue1()) count++;
//...
return count;
}
然后我會(huì)rules用
Rule bestRule = rules.stream().max(Comparator.comparingInt(r -> r.getScore(sale, product)));
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