嘗試在 python 2.7 中創(chuàng)建決策菜單。不能讓選項是個人的，而不是按順序排列的。除了if給出語法錯誤之外的任何東西pc = 英鎊換算kc = 千克換算cont = 1while cont == 1: if input("Would you like to convert to pounds or kilograms?") == 'pounds': pc = 1 if pc == 1: kilograms = float(input("Enter the amount of kilograms: ")) pounds = kilograms / 2.205 print('The amount of pounds you entered is ', kilograms, ' This is ', pounds, ' pounds ') pc = 0 if input('Do you want to go again? (y/n) ') == 'n': cont = 0 if input("Would you like to convert to pounds or kilograms?") == "kilograms": kc = 1 if kc == 1: pounds = float(input("Enter the amount of pounds: ")) kilograms = pounds * 2.2 grams = kilograms * 1000 print('The amount of pounds you entered is ', pounds, ' This is ', kilograms, ' kilograms ', 'and', grams, 'grams' ) kc = 0 if input('Do you want to go again? (y/n) ') == 'n': cont = 0在kilograms第一次提示時輸入“PC未定義”并且程序只有在您輸入poundsfirst, kilogramssecond時才能正常運行
2 回答
斯蒂芬大帝
TA貢獻1827條經驗 獲得超8個贊
while True: #generic while statement, only way to exit is break
choice = input("Would you like to convert to pounds or kilograms: ") #store our choice in a variable for later
if choice == 'pounds':
kilograms = float(input("Enter the amount of kilograms: "))
pounds = kilograms / 2.205
print('The amount of killograms you entered is ', kilograms,
' This is ', pounds, ' pounds ')
elif choice == "kilograms": #use an elif and define a different specific statement
pounds = float(input("Enter the amount of pounds: "))
kilograms = pounds * 2.2
grams = kilograms * 1000
print('The amount of pounds you entered is ', pounds,
' This is ', kilograms, ' kilograms ', 'and', grams,
'grams' )
elif choice == "quit":
print("Goodbye!")
break #use break to break out of a loop
else: #use an else to define a generic statement
print "%s is not a valid choice"%choice
continue #use continue to return to the beginning of the loop without doing anything after
do_continue = input('Do you want to go again? (y/n) ')
if do_continue == 'y':
pass #do nothing and continue
elif do_continue == 'n':
print("Goodbye!")
break
else:
print("What language is that? We will go again anyways!")
慕萊塢森
TA貢獻1810條經驗 獲得超4個贊
您的代碼中有一個“錯誤”。
該變量pc僅在第一次提示時才定義 == 'pounds'。因此，您會pc is not defined在第 7 行收到錯誤消息，因為它僅在您輸入“磅”時才被定義。
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