我有一個(gè)菜單功能和選擇功能都有效。有 3 種菜單選擇。1 和 3 在某一時(shí)刻正常工作。2從來(lái)沒(méi)有。我不知道我做了什么把它搞砸了，但是當(dāng)我運(yùn)行模塊以通過(guò) IDLE 進(jìn)行測(cè)試時(shí)，它在第一次提示輸入我的菜單選項(xiàng)編號(hào)之后就無(wú)法正常工作。它應(yīng)該完成一個(gè) if 語(yǔ)句，然后重新啟動(dòng)。我不知道還能?chē)L試什么。我希望我知道我改變了什么來(lái)搞砸它。tribbles = 1modulus = 2closer= 3def menu(): print(' -MENU-') print('1: Tribbles Exchange') print('2: Odd or Even?') print("3: I'm not in the mood...")menu()def choice(): choice = int(input('\n Enter the number of your menu choice: ')if choice == tribbles: bars = int(input('\n How many bars of gold-pressed latinum do you have? ')) print('\n You can buy ',bars * 5000 / 1000,' Tribbles.') menu() choice()elif choice == modulus: num = int(input('\n Enter any number:')) o_e = num % 2 if num == 0: print(num,' is an even number') elif num == 1: print(num,' is an odd number') menu() choice()elif choice == closer: print('\n Thanks for playing!') exit()else: print('Invalid entry. Please try again...') menu() choice()print(' ')choice = int(input('\n Enter the number of your menu choice: '))我希望它返回字符串加上所有公式結(jié)果，然后再次詢問(wèn)，除非選擇了選項(xiàng) 3 并執(zhí)行了 exit()。但是，它在第一次輸入后返回“輸入您的菜單選項(xiàng)的編號(hào)：”，然后在第二個(gè)提示符上選擇任何其他選項(xiàng)后返回空白。f
2 回答
忽然笑
TA貢獻(xiàn)1806條經(jīng)驗(yàn) 獲得超5個(gè)贊
在檢查 的值之前，未聲明choice該變量。choice您必須在以下行之前捕獲您的輸入：if choice == tribbles:. 您只是在定義一個(gè)函數(shù)，它甚至不返回您選擇的值或設(shè)置全局變量。
試試這個(gè)：
def menu():
print(' -MENU-')
print('1: Tribbles Exchange')
print('2: Odd or Even?')
print("3: I'm not in the mood...")
menu()
choice = int(input('\n Enter the number of your menu choice: '))
if choice == tribbles:
...
繁星點(diǎn)點(diǎn)滴滴
TA貢獻(xiàn)1803條經(jīng)驗(yàn) 獲得超3個(gè)贊
最好在文件頂部定義所有函數(shù)，并在底部調(diào)用這些函數(shù)！其次，您的縮進(jìn)不正確，我假設(shè)您將其粘貼到此處后發(fā)生了這種情況。最后，您永遠(yuǎn)不會(huì)真正調(diào)用該函數(shù)choice()，而是用提示的結(jié)果覆蓋它。
下面我將糾正這些問(wèn)題。
tribbles = 1
modulus = 2
closer= 3
def menu():
print(' -MENU-')
print('1: Tribbles Exchange')
print('2: Odd or Even?')
print("3: I'm not in the mood...")
choice() #added call to choice here because you always call choice after menu
def choice():
my_choice = int(raw_input('\nEnter the number of your menu choice: ')) #you were missing a ) here! and you were overwriting the function choice again
#changed choice var to my_choice everywhere
if my_choice == tribbles:
bars = int(raw_input('\nHow many bars of gold-pressed latinum do you have? '))
print('\n You can buy ',bars * 5000 / 1000,' Tribbles.')
menu()
elif my_choice == modulus:
num = int(raw_input('\n Enter any number:'))
o_e = num % 2
if num == 0:
print(num,' is an even number')
elif num == 1:
print(num,' is an odd number')
menu()
elif choice == closer:
print('\n Thanks for playing!')
exit()
else:
print('Invalid entry. Please try again...')
menu()
print(' ')
if __name__ == "__main__": #standard way to begin. This makes sure this is being called from this file and not when being imported. And it looks pretty!
menu()
添加回答
舉報(bào)
0/150
提交
取消