我正在嘗試編寫一段代碼，該代碼將對(duì)由于同步引起的系統(tǒng)時(shí)間變化做出反應(yīng)。這是一個(gè)在 goroutine 內(nèi)部運(yùn)行的相當(dāng)簡(jiǎn)單的代碼：var start, end time.Timevar start_ts, end_ts int64var diff_ts time.Durationvar diff time.Durationfor {    start = time.Now()    start_ts = start.Unix()    fmt.Printf("Now: => %v (%d);\n", start, start_ts)    time.Sleep(1 * time.Second)    end = time.Now()    end_ts = end.Unix()    fmt.Printf("New Now: %v (%d);\n", end, end_ts)    diff = end.Sub(start)    diff_ts = time.Duration(end_ts-start_ts) * time.Second    fmt.Printf("Measured time duration: %v (%v) %f (%f)\n", diff, diff_ts, diff.Seconds(), diff_ts.Seconds())}我的問(wèn)題是，當(dāng)我在另一個(gè)控制臺(tái)中更改系統(tǒng)時(shí)間時(shí)，時(shí)間讀取正確，但是“原始”時(shí)差不正確，我不得不求助于手動(dòng)構(gòu)建時(shí)差。以下是日志的摘錄：Now: => 2020-02-26 12:29:42.778827718 +0000 UTC m=+21.776791756 (1582720182);New Now: 2017-01-01 01:02:03.391215325 +0000 UTC m=+22.777003266 (1483232523);Measured time duration: 1.00021151s (-27635h27m39s) 1.000212 (-99487659.000000)diff 對(duì)象為什么會(huì)返回 1 秒，即使差異明顯大于那？