如何從很長(zhǎng)的 ping 命令輸出中獲取 ping 統(tǒng)計(jì)信息：func main() { cmdout, _ := exec.Command("ping", "127.0.0.1", "-n", "30000").Output() fmt.Printf("%s\n", cmdout)}我只需要這個(gè)輸出：Ping statistics for 127.0.0.1: Packets: Sent = 30000, Received = 30000, Lost = 0 (0% loss),Approximate round trip times in milli-seconds: Minimum = 0ms, Maximum = 0ms, Average = 0ms輸出如下：Reply from 127.0.0.1: bytes=32 time<1ms TTL=128Reply from 127.0.0.1: bytes=32 time<1ms TTL=128Reply from 127.0.0.1: bytes=32 time<1ms TTL=128...............................................我只想丟棄。我正在考慮將所有這些輸出放入一個(gè)變量中，然后對(duì)其進(jìn)行解析，直到我得到所需的結(jié)果：output := string(out) scanner := bufio.NewScanner(strings.NewReader(output)) for scanner.Scan() { fmt.Println("Line: ", scanner.Text()) regex compile etc... }但是，我不確定這是實(shí)現(xiàn)這一目標(biāo)的有效模式，通過(guò)選擇這種方式意味著用大量未使用的數(shù)據(jù)填充 RAM，這不是我在看的。我說(shuō)的對(duì)嗎？
1 回答
皈依舞
TA貢獻(xiàn)1851條經(jīng)驗(yàn) 獲得超3個(gè)贊
我認(rèn)為以下代碼是我需要的：
func main() {
args := "-n 30000 127.0.0.1"
cmd := exec.Command("ping", strings.Split(args, " ")...)
output, _ := cmd.StdoutPipe()
cmd.Start()
scanner := bufio.NewScanner(output)
for scanner.Scan() {
m := scanner.Text()
matchPackets, _ := regexp.MatchString("Packets", m)
matchMinimum, _ := regexp.MatchString("Minimum", m)
if matchPackets {
fmt.Println("Ping statistics for 127.0.0.1")
fmt.Println(m)
}
if matchMinimum {
fmt.Println("Approximate round trip times in milli-seconds:")
fmt.Println(m)
}
}
cmd.Wait()
}
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