顯然，我想根據(jù)函數(shù)參數(shù)（getOccupationStructs 函數(shù)）返回一個(gè)結(jié)構(gòu)數(shù)組，以保持 DRY （不在所有其他函數(shù)中使用 if else ），但這似乎不可能，所以這是我的錯(cuò)誤： cannot use []Student literal (type []Student) as type []struct {} in   return argument cannot use []Employee literal (type []Employee ) as type []struct {} in   return argument這是我的代碼：package mainimport (    "fmt"    "time"    "github.com/jinzhu/gorm"    _ "github.com/jinzhu/gorm/dialects/postgres")type Human struct {    ID          uint        `gorm:"primary_key" gorm:"column:_id" json:"_id"`    Name        string      `gorm:"column:name" json:"name"`    Age         int         `gorm:"column:age" json:"age"`    Phone       string      `gorm:"column:phone" json:"phone"`}type Student struct {    Human     School      string      `gorm:"column:school" json:"school"`    Loan        float32     `gorm:"column:loan" json:"loan"`}type Employee struct {    Human     Company     string      `gorm:"column:company" json:"company"`    Money       float32     `gorm:"column:money" json:"money"`}func getOccupationStructs(occupation string) []struct{} {    switch occupation {        case "student":            return []main.Student{}        case "employee":            return []main.Employee{}        default:            return []main.Student{}    }}func firstFunction(){    m := getOccupationStructs("student")    for _, value := range m{        fmt.Println("Hi, my name is "+value.Name+" and my school is "+value.School)    }}func secondFunction(){    m := getOccupationStructs("employee")    for _, value := range m{        fmt.Println("Hi, my name is "+value.Name+" and my company is "+value.Company)    }}是否有任何有效的解決方法來(lái)解決這個(gè)問(wèn)題？