我像這樣加密：  plaintextstr := "0000000000000thankustackoverflow"  plaintext := []byte(plaintextstr)  key := []byte("abcdefghijklmnop")  block, _ := aes.NewCipher(key)  ciphertext := make([]byte, aes.BlockSize+len(plaintext))  iv := ciphertext[:aes.BlockSize]  mode := cipher.NewCBCEncrypter(block, iv)  mode.CryptBlocks(ciphertext[aes.BlockSize:], plaintext)  fmt.Printf("%x\n", ciphertext)輸出是：000000000000000000000000000000000d77aa6646bb541808ed23c88d4b06d30f42b01d6e806a02b29086bc82892334f但是用 PHP 編寫的此代碼的另一個版本的輸出是：d77aa6646bb541808ed23c88d4b06d30f42b01d6e806a02b29086bc82892334fbf21ea861abbc3d72e44731978bb76c2請注意，00000000000000000000000000000000 是末尾缺失數(shù)據(jù)的確切長度。它是 32，即原始純文本字符串的大小。知道如何在 golang 中左移所有內(nèi)容并獲取丟失的數(shù)據(jù)嗎？PHP：<?phpinclude('Crypt/AES.php');$aes = new Crypt_AES();$aes->setKey('abcdefghijklmnop');echo bin2hex($aes->encrypt("0000000000000thankustackoverflow"));https://github.com/andrewarrow/phpseclib1/blob/master/Crypt/AES.php https://github.com/andrewarrow/phpseclib1/blob/master/Crypt/Rijndael.php調(diào)試php輸出：00000000000000000000000000000000 <--- IV30303030303030303030303030746861 block 0d77aa6646bb541808ed23c88d4b06d30 crypted 06e6b75737461636b6f766572666c6f77 block 16f42b01d6e806a02b29086bc82892334f crypted 1610101010101010101010101010101010 block 32bf21ea861abbc3d72e44731978bb76c2 crypted 32