這應(yīng)該是判斷郵件的 最好逐個解釋下^(\w+((-\w+)|(\.\w+))*)\+\w+((-\w+)|(\.\w+))*\@[A-Za-z0-9]+((\.|-)[A-Za-z0-9]+)*\.[A-Za-z0-9]+$
2 回答
弒天下
TA貢獻1818條經(jīng)驗 獲得超8個贊
匹配中文字符的正則表達式： [\u4e00-\u9fa5]
匹配雙字節(jié)字符(包括漢字在內(nèi))：[^\x00-\xff]
匹配空行的正則表達式：\n[\s| ]*\r
匹配HTML標(biāo)記的正則表達式：/<(.*)>.*<\/\1>|<(.*) \/>/
匹配首尾空格的正則表達式：(^\s*)|(\s*$)
匹配Email地址的正則表達式：\w+([-+.]\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*
匹配網(wǎng)址URL的正則表達式：http://([\w-]+\.)+[\w-]+(/[\w- ./?%&=]*)?
(1)應(yīng)用：計算字符串的長度（一個雙字節(jié)字符長度計2，ASCII字符計1）
String.prototype.len=function(){return this.replace([^\x00-\xff]/g,"aa").length;}
(2)應(yīng)用：javascript中沒有像vbscript那樣的trim函數(shù)，我們就可以利用這個表達式來實現(xiàn)
String.prototype.trim = function()
{
return this.replace(/(^\s*)|(\s*$)/g, "");
}
(3)應(yīng)用：利用正則表達式分解和轉(zhuǎn)換IP地址
function IP2V(ip) //IP地址轉(zhuǎn)換成對應(yīng)數(shù)值
{
re=/(\d+)\.(\d+)\.(\d+)\.(\d+)/g //匹配IP地址的正則表達式
if(re.test(ip))
{
return RegExp.$1*Math.pow(255,3))+RegExp.$2*Math.pow(255,2))+RegExp.$3*255+RegExp.$4*1
}
else
{
throw new Error("Not a valid IP address!")
}
}
(4)應(yīng)用：從URL地址中提取文件名的javascript程序
s="http://www.9499.net/page1.htm";
s=s.replace(/(.*\/){0,}([^\.]+).*/ig,"$2") ; //Page1.htm
(5)應(yīng)用：利用正則表達式限制網(wǎng)頁表單里的文本框輸入內(nèi)容
用正則表達式限制只能輸入中文：onkeyup="value=value.replace(/[^\u4E00-\u9FA5]/g,'')" onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\u4E00-\u9FA5]/g,''))"
用正則表達式限制只能輸入全角字符： onkeyup="value=value.replace(/[^\uFF00-\uFFFF]/g,'')" onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\uFF00-\uFFFF]/g,''))"
用正則表達式限制只能輸入數(shù)字：onkeyup="value=value.replace(/[^\d]/g,'') "onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\d]/g,''))"
用正則表達式限制只能輸入數(shù)字和英文：onkeyup="value=value.replace(/[\W]/g,'') "onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\d]/g,''))"
====================================================
正則表達式大全
正則表達式用于字符串處理，表單驗證等場合，實用高效，但用到時總是不太把握，以致往往要上網(wǎng)查一番。我將一些常用的表達式收藏在這里，作備忘之用。本貼隨時會更新。
匹配中文字符的正則表達式： [\u4e00-\u9fa5]
匹配雙字節(jié)字符(包括漢字在內(nèi))：[^\x00-\xff]
應(yīng)用：計算字符串的長度（一個雙字節(jié)字符長度計2，ASCII字符計1）
String.prototype.len=function(){return this.replace([^\x00-\xff]/g,"aa").length;}
匹配空行的正則表達式：\n[\s| ]*\r
匹配HTML標(biāo)記的正則表達式：/<(.*)>.*<\/\1>|<(.*) \/>/
匹配首尾空格的正則表達式：(^\s*)|(\s*$)
應(yīng)用：javascript中沒有像vbscript那樣的trim函數(shù)，我們就可以利用這個表達式來實現(xiàn)，如下：
String.prototype.trim = function()
{
return this.replace(/(^\s*)|(\s*$)/g, "");
}
利用正則表達式分解和轉(zhuǎn)換IP地址：
下面是利用正則表達式匹配IP地址，并將IP地址轉(zhuǎn)換成對應(yīng)數(shù)值的javascript程序：
function IP2V(ip)
{
re=/(\d+)\.(\d+)\.(\d+)\.(\d+)/g //匹配IP地址的正則表達式
if(re.test(ip))
{
return RegExp.$1*Math.pow(255,3))+RegExp.$2*Math.pow(255,2))+RegExp.$3*255+RegExp.$4*1
}
else
{
throw new Error("Not a valid IP address!")
}
}
不過上面的程序如果不用正則表達式，而直接用split函數(shù)來分解可能更簡單，程序如下：
var ip="10.100.20.168"
ip=ip.split(".")
alert("IP值是："+(ip[0]*255*255*255+ip[1]*255*255+ip[2]*255+ip[3]*1))
匹配Email地址的正則表達式：\w+([-+.]\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*
匹配網(wǎng)址URL的正則表達式：http://([\w-]+\.)+[\w-]+(/[\w- ./?%&=]*)?
利用正則表達式去除字串中重復(fù)的字符的算法程序：[注：此程序不正確，原因見本貼回復(fù)]
var s="abacabefgeeii"
var s1=s.replace(/(.).*\1/g,"$1")
var re=new RegExp("["+s1+"]","g"?瓊?渦獢p?????浜睹扥潛桴牥摜極慢?瑨m?)
var s2=s.replace(re,"")
alert(s1+s2) //結(jié)果為：abcefgi
我原來在CSDN上發(fā)貼尋求一個表達式來實現(xiàn)去除重復(fù)字符的方法，最終沒有找到，這是我能想到的最簡單的實現(xiàn)方法。思路是使用后向引用取出包括重復(fù)的字符，再以重復(fù)的字符建立第二個表達式，取到不重復(fù)的字符，兩者串連。這個方法對于字符順序有要求的字符串可能不適用。
得用正則表達式從URL地址中提取文件名的javascript程序，如下結(jié)果為page1
s="http://www.9499.net/page1.htm"
s=s.replace(/(.*\/){0,}([^\.]+).*/ig,"$2")
alert(s)
利用正則表達式限制網(wǎng)頁表單里的文本框輸入內(nèi)容：
用正則表達式限制只能輸入中文：onkeyup="value=value.replace(/[^\u4E00-\u9FA5]/g,'')" onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\u4E00-\u9FA5]/g,''))"
用正則表達式限制只能輸入全角字符： onkeyup="value=value.replace(/[^\uFF00-\uFFFF]/g,'')" onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\uFF00-\uFFFF]/g,''))"
用正則表達式限制只能輸入數(shù)字：onkeyup="value=value.replace(/[^\d]/g,'') "onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\d]/g,''))"
用正則表達式限制只能輸入數(shù)字和英文：onkeyup="value=value.replace(/[\W]/g,'') "onbeforepaste="clipboardData.setData('text',clipboardData.getData('text').replace(/[^\d]/g,''))"
補充：
^\d+$ //匹配非負(fù)整數(shù)（正整數(shù) + 0）
^[0-9]*[1-9][0-9]*$ //匹配正整數(shù)
^((-\d+)|(0+))$ //匹配非正整數(shù)（負(fù)整數(shù) + 0）
^-[0-9]*[1-9][0-9]*$ //匹配負(fù)整數(shù)
^-?\d+$ //匹配整數(shù)
^\d+(\.\d+)?$ //匹配非負(fù)浮點數(shù)（正浮點數(shù) + 0）
^(([0-9]+\.[0-9]*[1-9][0-9]*)|([0-9]*[1-9][0-9]*\.[0-9]+)|([0-9]*[1-9][0-9]*))$ //匹配正浮點數(shù)
^((-\d+(\.\d+)?)|(0+(\.0+)?))$ //匹配非正浮點數(shù)（負(fù)浮點數(shù) + 0）
^(-(([0-9]+\.[0-9]*[1-9][0-9]*)|([0-9]*[1-9][0-9]*\.[0-9]+)|([0-9]*[1-9][0-9]*)))$ //匹配負(fù)浮點數(shù)
^(-?\d+)(\.\d+)?$ //匹配浮點數(shù)
^[A-Za-z]+$ //匹配由26個英文字母組成的字符串
^[A-Z]+$ //匹配由26個英文字母的大寫組成的字符串
^[a-z]+$ //匹配由26個英文字母的小寫組成的字符串
^[A-Za-z0-9]+$ //匹配由數(shù)字和26個英文字母組成的字符串
^\w+$ //匹配由數(shù)字、26個英文字母或者下劃線組成的字符串
^[\w-]+(\.[\w?瓊?渦獢p?????浜睹扥潛桴牥摜極慢?瑨m?-]+)*@[\w-]+(\.[\w-]+)+$ //匹配email地址
^[a-zA-z]+://匹配(\w+(-\w+)*)(\.(\w+(-\w+)*))*(\?\S*)?$ //匹配url
利用正則表達式去除字串中重復(fù)的字符的算法程序：
var s="abacabefgeeii"
var s1=s.replace(/(.).*\1/g,"$1")
var re=new RegExp("["+s1+"]","g")
var s2=s.replace(re,"")
alert(s1+s2) //結(jié)果為：abcefgi
===============================
如果var s = "abacabefggeeii"
結(jié)果就不對了，結(jié)果為：abeicfgg
正則表達式的能力有限
RE: totoro
謝謝你的指點，這個javascript正則表達式程序算法確實有問題，我會試著找更好的辦法!!!
1.確認(rèn)有效電子郵件格式
下面的代碼示例使用靜態(tài) Regex.IsMatch 方法驗證一個字符串是否為有效電子郵件格式。如果字符串包含一個有效的電子郵件地址，則 IsValidEmail 方法返回 true，否則返回 false，但不采取其他任何操作。您可以使用 IsValidEmail，在應(yīng)用程序?qū)⒌刂反鎯υ跀?shù)據(jù)庫中或顯示在 ASP.NET 頁中之前，篩選出包含無效字符的電子郵件地址。
[Visual Basic]
Function IsValidEmail(strIn As String) As Boolean
' Return true if strIn is in valid e-mail format.
Return Regex.IsMatch(strIn, ("^([\w-\.]+)@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([\w-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)$")
End Function
[C#]
bool IsValidEmail(string strIn)
{
// Return true if strIn is in valid e-mail format.
return Regex.IsMatch(strIn, @"^([\w-\.]+)@((\[[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.)|(([\w-]+\.)+))([a-zA-Z]{2,4}|[0-9]{1,3})(\]?)$");
}
2.清理輸入字符串
下面的代碼示例使用靜態(tài) Regex.Replace 方法從字符串中抽出無效字符。您可以使用這里定義的 CleanInput 方法，清除掉在接受用戶輸入的窗體的文本字段中輸入的可能有害的字符。CleanInput 在清除掉除 @、-（連字符）和 .（句點）以外的所有非字母數(shù)字字符后返回一個字符串。
[Visual Basic]
Function CleanInput(strIn As String) As String
' Replace invalid characters with empty strings.
Return Regex.Replace(strIn, "[^\w\.@-]", "")
End Function
[C#]
String CleanInput(string strIn)
?瓊?渦獢p?????浜睹扥潛桴牥摜極慢?瑨m?{
// Replace invalid characters with empty strings.
return Regex.Replace(strIn, @"[^\w\.@-]", "");
}
3.更改日期格式
以下代碼示例使用 Regex.Replace 方法來用 dd-mm-yy 的日期形式代替 mm/dd/yy 的日期形式。
[Visual Basic]
Function MDYToDMY(input As String) As String
Return Regex.Replace(input, _
"\b(?<month>\d{1,2})/(?<day>\d{1,2})/(?<year>\d{2,4})\b", _
"${day}-${month}-${year}")
End Function
[C#]
String MDYToDMY(String input)
{
return Regex.Replace(input,
"\\b(?<month>\\d{1,2})/(?<day>\\d{1,2})/(?<year>\\d{2,4})\\b",
"${day}-${month}-${year}");
}
Regex 替換模式
本示例說明如何在 Regex.Replace 的替換模式中使用命名的反向引用。其中，替換表達式 ${day} 插入由 (?<day>...) 組捕獲的子字符串。
有幾種靜態(tài)函數(shù)使您可以在使用正則表達式操作時無需創(chuàng)建顯式正則表達式對象，而 Regex.Replace 函數(shù)正是其中之一。如果您不想保留編譯的正則表達式，這將給您帶來方便
4.提取 URL 信息
以下代碼示例使用 Match.Result 來從 URL 提取協(xié)議和端口號。例如，“http://www.contoso.com:8080/letters/readme.html”將返回“http:8080”。
[Visual Basic]
Function Extension(url As String) As String
Dim r As New Regex("^(?<proto>\w+)://[^/]+?(?<port>:\d+)?/", _
RegexOptions.Compiled)
Return r.Match(url).Result("${proto}${port}")
End Function
[C#]
String Extension(String url)
{
Regex r = new Regex(@"^(?<proto>\w+)://[^/]+?(?<port>:\d+)?/",
RegexOptions.Compiled);
return r.Match(url).Result("${proto}${port}");
}
今天有網(wǎng)友問：如何用正則表達式表示要么是數(shù)字要么是字母 是字母的話只能是一個字母 數(shù)字則無所謂？
我的回答是：
^[a-zA-Z]$|^\d+$
慕姐4208626
TA貢獻1852條經(jīng)驗 獲得超7個贊
^(\w+((-\w+)|(\.\w+))*)\+\w+((-\w+)|(\.\w+))*\@[A-Za-z0-9]+((\.|-)[A-Za-z0-9]+)*\.[A-Za-z0-9]+$
Assert position at the beginning of the string ?^?
Match the regular expression below and capture its match into backreference number 1 ?(\w+((-\w+)|(\.\w+))*)?
Match a single character that is a “word character” (letters, digits, etc.) ?\w+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
Match the regular expression below and capture its match into backreference number 2 ?((-\w+)|(\.\w+))*?
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) ?*?
Note: You repeated the capturing group itself. The group will capture only the last iteration. Put a capturing group around the repeated group to capture all iterations. ?*?
Match either the regular expression below (attempting the next alternative only if this one fails) ?(-\w+)?
Match the regular expression below and capture its match into backreference number 3 ?(-\w+)?
Match the character “-” literally ?-?
Match a single character that is a “word character” (letters, digits, etc.) ?\w+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
Or match regular expression number 2 below (the entire group fails if this one fails to match) ?(\.\w+)?
Match the regular expression below and capture its match into backreference number 4 ?(\.\w+)?
Match the character “.” literally ?\.?
Match a single character that is a “word character” (letters, digits, etc.) ?\w+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
Match the character “+” literally ?\+?
Match a single character that is a “word character” (letters, digits, etc.) ?\w+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
Match the regular expression below and capture its match into backreference number 5 ?((-\w+)|(\.\w+))*?
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) ?*?
Note: You repeated the capturing group itself. The group will capture only the last iteration. Put a capturing group around the repeated group to capture all iterations. ?*?
Match either the regular expression below (attempting the next alternative only if this one fails) ?(-\w+)?
Match the regular expression below and capture its match into backreference number 6 ?(-\w+)?
Match the character “-” literally ?-?
Match a single character that is a “word character” (letters, digits, etc.) ?\w+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
Or match regular expression number 2 below (the entire group fails if this one fails to match) ?(\.\w+)?
Match the regular expression below and capture its match into backreference number 7 ?(\.\w+)?
Match the character “.” literally ?\.?
Match a single character that is a “word character” (letters, digits, etc.) ?\w+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
Match the character “@” literally ?\@?
Match a single character present in the list below ?[A-Za-z0-9]+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
A character in the range between “A” and “Z” ?A-Z?
A character in the range between “a” and “z” ?a-z?
A character in the range between “0” and “9” ?0-9?
Match the regular expression below and capture its match into backreference number 8 ?((\.|-)[A-Za-z0-9]+)*?
Between zero and unlimited times, as many times as possible, giving back as needed (greedy) ?*?
Note: You repeated the capturing group itself. The group will capture only the last iteration. Put a capturing group around the repeated group to capture all iterations. ?*?
Match the regular expression below and capture its match into backreference number 9 ?(\.|-)?
Match either the regular expression below (attempting the next alternative only if this one fails) ?\.?
Match the character “.” literally ?\.?
Or match regular expression number 2 below (the entire group fails if this one fails to match) ?-?
Match the character “-” literally ?-?
Match a single character present in the list below ?[A-Za-z0-9]+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
A character in the range between “A” and “Z” ?A-Z?
A character in the range between “a” and “z” ?a-z?
A character in the range between “0” and “9” ?0-9?
Match the character “.” literally ?\.?
Match a single character present in the list below ?[A-Za-z0-9]+?
Between one and unlimited times, as many times as possible, giving back as needed (greedy) ?+?
A character in the range between “A” and “Z” ?A-Z?
A character in the range between “a” and “z” ?a-z?
A character in the range between “0” and “9” ?0-9?
Assert position at the end of the string (or before the line break at the end of the string, if any) ?$?
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