我有一本看起來像這樣的字典：{ "month": ["January", "February", "March"], "volume": [1,2,3], "target": [6,8,5]}我想遍歷每個鍵和值，以便我可以制作一個如下所示的列表：["month: January, volume: 1, target: 6", "month: February, volume: 2, target: 8", "month: March, volume: 3, target: 5"]如何逐個循環(huán)遍歷每個鍵值，直到到達最后一個列表的數(shù)組值的末尾？對于每個鍵，所有列表的長度相同。
3 回答
呼喚遠方
TA貢獻1856條經(jīng)驗 獲得超11個贊
d = {
"month": ["January", "February", "March"],
"volume": [1,2,3],
"target": [6,8,5]
}
keys = tuple(d) # ('month', 'volume', 'target')
values = tuple(zip(*d.values())) # (('January', 1, 6), ('February', 2, 8), ('March', 3, 5))
your_list = [
', '.join(
f'{keys[i]}: {value[i]}'
for i in range(len(keys)) # range(3) in this case
)
for value in values
]
print(your_list)
輸出：
['month: January, volume: 1, target: 6',
'month: February, volume: 2, target: 8',
'month: March, volume: 3, target: 5']
湖上湖
TA貢獻2003條經(jīng)驗 獲得超2個贊
使用這個例子：
di = {
"month": ["January", "February", "March"],
"volume": [1,2,3],
"target": [6,8,5],
}
一個想法是將其轉(zhuǎn)換為列表
li = [ [k + ": " +str(v) for v in v_list] for k,v_list in test_dict.items()]
然后使用 zip 進行連接
[ ', '.join(l) for l in zip(*li) ]
這是結(jié)果：
['month: January, volume: 1, target: 6',
'month: February, volume: 2, target: 8',
'month: March, volume: 3, target: 5']
偶然的你
TA貢獻1841條經(jīng)驗 獲得超3個贊
假設(shè)所有值具有相同的長度：
di = {
"month": ["January", "February", "March"],
"volume": [1,2,3],
"target": [6,8,5],
}
sample_length = len(list(di.values())[0])
final_list = []
for j in range(sample_length):
list_item = []
for key, val in di.items():
list_item.append('{}: {}'.format(key, val[j]))
final_list.append(', '.join(list_item))
print(final_list)
輸出：
['month: January, volume: 1, target: 6', 'month: February, volume: 2, target: 8', 'month: March, volume: 3, target: 5']
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