我有一個包含多個子文件夾的文件夾，每個子文件夾里面都有一個文件。我正在使用 python 并希望使用關聯(lián)的子文件夾名稱加上舊文件名重命名文件以成為新文件名。我已經(jīng)能夠獲得子文件夾和文件名的列表，os.walk()但是我在更改文件名時遇到了問題。def list_files(dir): r = [] for root, dirs, files in os.walk(dir): for name in files: r.append(os.path.join(root, name)) os.rename(name, r)我得到錯誤：類型錯誤：重命名：dst 應該是字符串、字節(jié)或 os.PathLike，而不是列表當我返回 r 時，我得到了根目錄和文件名，但無法更改文件名。感謝任何幫助。
2 回答
12345678_0001
TA貢獻1802條經(jīng)驗 獲得超5個贊
import os
def list_files(dir):
sub_folders = os.listdir(dir)
for sub_folder in sub_folders:
sub_folder_path = os.path.join(dir,sub_folder)
for root, dirs, files in os.walk(sub_folder_path):
for file in files:
new_filename = root.replace(dir, "").replace(os.path.sep,"_").strip("_")+"_" + file
os.rename(os.path.join(root, file), os.path.join(root, new_filename))
input_dir = ""
assert os.path.isdir(input_dir),"Enter a valid directory path which consists of sub-directories"
list_files(input_dir)
這將為多個子目錄而不是嵌套目錄完成這項工作。如果要更改文件名的格式，請更改new_filename = sub_folder+ "" + file.
互換的青春
TA貢獻1797條經(jīng)驗 獲得超6個贊
它listdir()在兩個級別都使用，它檢查并忽略第一級子目錄中更深的嵌套目錄。
這是我的代碼，注釋很好：
import os
def collapse_dirs(dir):
# get a list of elements in the target directory
elems = os.listdir(dir)
# iterate over each element
for elem in elems:
# compute the path to the element
path = os.path.join(dir, elem)
# is it a directory? If so, process it...
if os.path.isdir(path):
# get all of the elements in the subdirectory
subelems = os.listdir(path)
# process each entry in this subdirectory...
for subelem in subelems:
# compute the full path to the element
filepath = os.path.join(path, subelem)
# we only want to proceed if the element is a file. If so...
if os.path.isfile(filepath):
# compute the new path for the file - I chose to separate the names with an underscore,
# but this line can easily be changed to use whatever separator you want (or none)
newpath = os.path.join(path, elem + '_' + subelem)
# rename the file
os.rename(filepath, newpath)
def main():
collapse_dirs('/tmp/filerename2')
main()
這是我在運行代碼之前的目標目錄：
filerename2
├── a
│ └── xxx.txt
├── b
│ ├── xxx.txt
│ └── yyyy
│ └── zzzz
├── c
│ └── xxx.txt
└── xxxx
這是之后：
filerename2
├── a
│ └── a_xxx.txt
├── b
│ ├── b_xxx.txt
│ └── yyyy
│ └── zzzz
├── c
│ └── c_xxx.txt
└── xxxx
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