計(jì)算器版本 1創(chuàng)建一個(gè)控制臺(tái)項(xiàng)目。將“Program.cs”重命名為“CalculatorRun.cs”添加類“Calculator.cs” - 具有三個(gè)公共屬性的 3 個(gè)私有雙數(shù)據(jù)成員 - firstOperand、FirstOperand；- 第二操作數(shù)，第二操作數(shù)；- 結(jié)果，結(jié)果；1 公共方法 Addition()在這個(gè)方法中做加法，Result = FirstOperand + SecondOperand;在“CalculatorRun.cs”中，讓用戶輸入 firstOperand 和 secondOperand 的值，顯示添加結(jié)果。我已經(jīng)為此工作了幾個(gè)小時(shí)，但仍然沒有任何意義。我的代碼沒用。有人有意見嗎？這就是我所擁有的：namespace CalculatorRun{ class Calculator { static void Main(string[] args) { decimal FirstOperand, SecondOperand, Result, result; Console.Write("Addition Calculation"); Console.Write(" \n\n"); Console.Write(" Enter first operand: "); FirstOperand = Convert.ToDecimal(Console.ReadLine()); Console.Write(" Enter second operand: "); SecondOperand = Convert.ToDecimal(Console.ReadLine()); Console.Write("-------------------------\n\n"); Result = FirstOperand + SecondOperand; result = Convert.ToDecimal(Result); Console.WriteLine("Addition Result: {0}", string.Format("{0}", result)); Console.WriteLine("Press any key to continue....."); Console.ReadLine(); } }}但它需要更像這樣（當(dāng)然使用頂部的說明）。但是當(dāng)我嘗試過它時(shí)，我無法讓它工作。：使用系統(tǒng)；namespace Calculator{ class Program { public static void Main(string[] args) { }//<----------- public int number01; public int number02; public int Number03 { get { return number02 / number01; } }//<---------- }}
1 回答
哆啦的時(shí)光機(jī)
TA貢獻(xiàn)1779條經(jīng)驗(yàn) 獲得超6個(gè)贊
這將為您完成。評(píng)論中的解釋：
using System;
namespace ConsoleApplication1 {
class Program {
static void Main( string[] args ) {
Calculator calculator = new Calculator();
Console.Write( " Enter first operand: " );
calculator.FirstOperand = Convert.ToDouble( Console.ReadLine() ); //get the first
Console.Write( " Enter first operand: " );
calculator.SecondOperand = Convert.ToDouble( Console.ReadLine() ); //get the second
calculator.Addition(); //Do addition
Console.WriteLine( "Addition Result: {0}", calculator.Result ); //show result
Console.WriteLine( "Press any key to continue....." );
Console.ReadLine();
}
}
class Calculator {
private double firstOperand, secondOperand, result; //double data members
//3 public properties
public double FirstOperand {
get { return firstOperand; }
set { firstOperand = value; }
}
public double SecondOperand {
get { return secondOperand; }
set { secondOperand = value; }
}
public double Result {
get { return result; }
set { result = value; }
}
//1 public method Addition()
public double Addition() {
return result = firstOperand + secondOperand;
}
}
}
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