我有兩個包含相似值的對象數(shù)組data = [array1, array2]array1 = [{hour: "565", age: "21", id: "1", naban: "sdfsd"}, {hour: "515", age: "25", id: "2", naban: "sf"}]array2 = [{hour: "56454", age: "21", id: "1", too: "898"}, {hour: "8979", age: "25", id: "2", too: "234234"},  {hour: "65465", age: "27", id: "6", too: "123"}]我有一個數(shù)組，其中這兩個對象集的值將用于合并keys= ['id', 'id']我想合并這些對象并創(chuàng)建一個對象數(shù)組，如下所示：result = [{hour: "565", hour2: "56454", age: "21", age2: "21", id: "1", too: "898", naban: "sdfsd"}, {hour: "515", hour2: "8979", age: "25", age2: "25", id: "2", too: "234234", naban: "sf"}, {hour: "65465", age: "27", id: "6", too: "123"} ]標(biāo)準(zhǔn)：我想保留所有不在鍵數(shù)組中的信息，例如。如果您查看結(jié)果數(shù)組，您將看到 hour 和 hour2 值。如果鍵不匹配，它將按原樣推送對象（例如結(jié)果數(shù)組中的第三項）這是我到目前為止所做的：mergeOjects = (object, keys) => {const sameKeys = Object.values(keys);const data = Object.values(object);if (data[0].length > data[1].length) {  const yarrak = data[0].map((item, i) => {    if (item[sameKeys[0]] === data[1][i][sameKeys[1]]) {      return Object.assign({}, item, data[1][i]);    }    return Object.assign({}, item);  });  console.log({ sameKeys, data, yarrak });} else {  const yarrak = data[1].map((item, i) => {    if (data[0][i]) {      if (item[sameKeys[1]] === data[0][i][sameKeys[0]]) {        return Object.assign({}, item, data[0][i]);      }    }    return Object.assign({}, item);  });  console.log({ sameKeys, data, yarrak });}};它可能需要一些清潔，但我現(xiàn)在正試圖讓邏輯工作，所以提前抱歉。我能夠完成第二個條件，但它會覆蓋小時值，而不是像示例中那樣單獨存儲