這是針對 headtails java 作業(yè)分配的，您可以在網(wǎng)上找到一些地方（例如http://www.javaproblems.com/2013/01/medium-problem-tricky-heads-and-tails.html）這個想法是輸入一個十進(jìn)制 0 到 511 并讓它輸出一個 3 x 3 的 H 或 T 矩陣，用于 0 或 1（我的作品是 0 到 255）這是我的嘗試，但我無法開始工作：public static void main(String[] args) { @SuppressWarnings("resource") Scanner keyboard = new Scanner(System.in); //System.out.println("Please enter a number between 0 and 511: "); //int num = keyboard.nextInt(); int num = 458; String binNum = ""; int temp; String[][] coinArr = new String[3][3]; // = [][]; while(num > 0) { temp = (int) (num % 2); binNum = binNum + "" + temp; num = (int) (num / 2); } System.out.println("binNum length is " + binNum.length()); System.out.println("binNum is " + binNum); binNum = String.format((binNum.length() < 9 ? ("%0"+ (9 - binNum.length())+"d%s") : "%0$d%s"), 0 ,binNum); System.out.println("binNum length is " + binNum.length()); System.out.println("binNum is " + binNum); int k=0; for(int i = 0; i < 3; i++) { for (int j = 0; j < 3; j++) { binNum = binNum.replaceAll("0", "H"); binNum = binNum.replaceAll("1", "T"); coinArr[i][j] = binNum.substring(k, k+1); k++; System.out.print(coinArr[i][j]); } System.out.println(); }}
2 回答
HUX布斯
TA貢獻(xiàn)1876條經(jīng)驗(yàn) 獲得超6個贊
您從十進(jìn)制到二進(jìn)制的轉(zhuǎn)換是錯誤的，正確的是：
while(num > 0)
{
temp = (int) (num % 2);
binNum = temp + "" + binNum;
num = (int) (num / 2);
}
那么你的 binNum 只需要 9 個字符：
binNum = binNum.length() < 9 ? String.format("%0"+ (9 - binNum.length())+"d%s", 0 ,binNum) : binNum;
// You don't need this inside your loop
binNum = binNum.replaceAll("0", "H");
binNum = binNum.replaceAll("1", "T");
int k=0;
for(int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
coinArr[i][j] = String.valueOf(binNum.charAt(k));
k++;
System.out.print(coinArr[i][j]);
}
System.out.println();
}
紅糖糍粑
TA貢獻(xiàn)1815條經(jīng)驗(yàn) 獲得超6個贊
有2個問題：-
1) 改變
binNum = binNum + "" + temp;
到
binNum = temp + binNum;
2) 改變
binNum = String.format((binNum.length() < 9 ? ("%0"+ (9 - binNum.length())+"d%s") : "%0$d%s"), 0 ,binNum);到
binNum = String.format("%09d", Integer.parseInt(binNum));添加回答
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