我正在學(xué)習(xí) Python 并且正在研究隨機擲骰子。當(dāng)我運行它時，它會重復(fù)在詢問您是否要再次播放后首先顯示的相同數(shù)字。我需要幫助找到我在這里出錯的地方。我嘗試移動代碼并放置不同種類的代碼。我只是被難住了。import sysimport randomimport timegreeting = "Welcome to my Dice Game!"roll = "Lets roll this die!"die = random.randint(0, 6)print(greeting)time.sleep(2)answer = input("Want to play?")while answer == "yes" or answer == "y": print(roll) time.sleep(2) print(die) answer = input("Want to play again?")print("Thanks for playing!")這就是我得到的：Welcome to my Dice Game!Want to play?yesLets roll this die!5Want to play again?yesLets roll this die!5Want to play again?yLets roll this die!5
2 回答
qq_笑_17
TA貢獻1818條經(jīng)驗 獲得超7個贊
您需要在每次循環(huán)中重新計算骰子的值，例如：
import sys
import random
import time
greeting = "Welcome to my Dice Game!"
roll = "Lets roll this die!"
print(greeting)
time.sleep(2)
answer = input("Want to play?")
while answer == "yes" or answer == "y":
print(roll)
time.sleep(2)
die = random.randint(0, 6) # recompute it here instead
print(die)
answer = input("Want to play again?")
print("Thanks for playing!")
GCT1015
TA貢獻1827條經(jīng)驗 獲得超4個贊
當(dāng)您運行該命令時die = random.randint(0, 6)，您告訴 Python 的是“使用該random.randint()函數(shù)在 1 到 6 之間選擇一個隨機整數(shù)，然后將名為的變量設(shè)置為die等于選擇的整數(shù)”。完成后，您的其余代碼不會執(zhí)行任何操作來更新 的值die。這意味著print(die)在循環(huán)中將繼續(xù)打印最初給出的任何值。換句話說，該命令die = random.randint(0, 6) 并不意味著“random.randint(0, 6)每次我提到時重新運行該命令并獲得另一個隨機數(shù)die”。相反，die它只是一些具有特定常量值的變量。
由于random.randint()實際數(shù)字生成是什么，保持更新的一種方法die是簡單地將您在循環(huán)外的命令移動到循環(huán)內(nèi)：
while answer == "yes" or answer == "y":
print(roll)
die = random.randint(0, 6) # Generate a new random number, then assign it to 'die'
time.sleep(2)
print(die)
answer = input("Want to play again?")
事實上，如果你除了打印數(shù)字之外沒有真正對數(shù)字做任何事情，你可以完全忘記使用一個變量，只需將random.randint()命令粘貼在你的print命令中：
while answer == "yes" or answer == "y":
print(roll)
time.sleep(2)
print(random.randint(0, 6))
answer = input("Want to play again?")
添加回答
舉報
0/150
提交
取消