#include "iostream"using namespace std;int main(){char *p[5] ;for (int i = 0; i < 5; i++){p[i] = (char *)calloc(100, sizeof(char));}cout << "please input an number such as \"one hundred"" and twenty five\"" << endl;for (int i = 0; i <= 5; i++){char ch = cin.get();while (ch != ' ' || ch != '\0'){*p[i]++ = ch;ch = cin.get();}if (ch == '\0') break;}for (int i = 0; i < 5; i++){cout << p[i];}return 0;}我想從鍵盤輸入到一段字符串，然后將這段字符串從空格處拆分開到一個指針數(shù)組里面，知道字符串結(jié)尾現(xiàn)在我我輸入 one hundred and twelve 的時候老是不成功請高手幫我看下
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躍然一笑
TA貢獻(xiàn)1826條經(jīng)驗 獲得超6個贊
1、cin.get函數(shù)不會接收到'\0'這種字符，輸入回車后結(jié)束輸出，因此接收到的應(yīng)該是'\n'。
2、while的循環(huán)條件，ch != ' ' || ch != '\n'(這里換成\n)，不等于空格或者不等于回車，那這不就是永遠(yuǎn)為真的？應(yīng)該是&&吧。
3、*p[i]++ = ch; p的指針已經(jīng)被++了，后面還怎么能當(dāng)做cout的首地址呢。
應(yīng)該改成這個樣子吧
char *p[5] ; char *q; for (int i = 0; i < 5; i++) { p[i] = (char *)calloc(100, sizeof(char)); } cout << "please input an number such as \"one hundred" " and twenty five\"" << endl; for (int i = 0; i <= 5; i++) { q = p[i]; char ch = cin.get(); while (ch != ' ' && ch != '\n') { *q++ = ch; ch = cin.get(); } if (ch == '\n') break; } for (int i = 0; i < 5; i++) { cout << p[i]; } |
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