3 回答

TA貢獻1784條經(jīng)驗 獲得超8個贊
我的解決方案,
實體行動:
@Entity
@Table(name = "actions")
public class Action {
@Id
private Integer id;
@OneToMany(mappedBy = "action")
private List<ActionLang> actionlang = new ArrayList<>();
public Action() { }
public Action(Integer id) {this.id = id;}
public Integer getId() {return id;}
public void setId(Integer id) {this.id = id;}
public List<ActionLang> getActionLang() {return actionlang;}
public void addActionLang(ActionLang actionlang) {
this.actionlang.add(actionlang);
}
public void removeActionLang(ActionLang actionlang) {
this.actionlang.remove(actionlang);
}
@Override
public String toString() {return "id: " + id ;}
}
實體 ActionLang,
@Entity
@Table(name = "actions_langs")
public class ActionLang {
@EmbeddedId
private ActionLangId id;
@ManyToOne(fetch = FetchType.LAZY)
@MapsId("actionId")
@JoinColumn(name = "actions_id", nullable = false)
@OnDelete(action = OnDeleteAction.CASCADE)
@JsonIgnore
private Action action;
@ManyToOne(fetch = FetchType.LAZY)
@MapsId("langId")
@JoinColumn(name = "langs_id", nullable = false)
@OnDelete(action = OnDeleteAction.CASCADE)
@JsonIgnore
private Lang lang;
@NotNull(message="null")
@Size(max = 45, message="short")
private String name;
public ActionLang() {}
public ActionLang(ActionLangId actionlangid, String name) {
this.id = actionlangid;
this.name = name;
}
public ActionLangId getId() {return id;}
public String getName() {return name;}
public void setName(String name) {this.name = name;}
public void setId(ActionLangId id) {this.id = id;}
public Action getAction() {return action;}
public void setAction(Action action) {this.action = action;}
public Lang getLang() {return lang;}
public void setLang(Lang lang) { this.lang = lang; }
@Override
public String toString() {return "ActionLang [id=" + id + ", name=" + name + "]"; }
}
服務(wù)
@Component
public class ActionDAOService {
@Autowired
private IActionDao actionRepository;
@Autowired
private IActionLangDao actionlangRepository;
@Transactional
public Action saveAction(Integer idlang, String name){
Lang lang = new Lang();
lang.setId(idlang);
Integer id = actionRepository.findActionId();
if(id == null) {
id=(Integer) 1;
}
Action action = new Action(id);
actionRepository.save(action);
ActionLang actionlang = new ActionLang(new ActionLangId(id, idlang),name);
action.addActionLang(actionlang);
actionlang.setAction(action);
actionlang.setLang(lang);
actionlangRepository.save(actionlang);
return action;
}
}

TA貢獻1906條經(jīng)驗 獲得超10個贊
實體動作
@Entity
@Table(name = "actions")
public class Action {
@Id
private Integer id;
@OneToMany(mappedBy = "action", cascade = CascadeType.ALL, orphanRemoval = true)
private List<ActionLang> actionlang = new ArrayList<>();
public Action() {
}
public Action(Integer id) {
super();
this.id = id;
}
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
public List<ActionLang> getActionlang() {
return actionlang;
}
@Override
public String toString() {
return "Action [id=" + id + ", actionlang=" + actionlang + ", getId()=" + getId() + ", getActionlang()="
+ getActionlang() + ", getClass()=" + getClass() + ", hashCode()=" + hashCode() + ", toString()="
+ super.toString() + "]";
}
}

TA貢獻1794條經(jīng)驗 獲得超8個贊
我已經(jīng)修改了服務(wù),但出現(xiàn)了同樣的錯誤
@Transactional
public Action saveAction(Integer idlang, String name){
Integer id = actionRepository.findActionId();
if(id == null) {id=(Integer) 1;}
Action action = new Action(id);
ActionLang actionlang = new ActionLang(new ActionLangId(id, idlang),name);
action.getActionlang().add(actionlang);
actionRepository.save(action);
return action;
}
動作的結(jié)構(gòu)是這樣的:
{
"id": 2,
"actionlang": [
{
"id": {
"actionId": 2,
"langId": 1
},
"name": "hkjhlhklhkll?k?l"
}
]
}
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