首頁(yè) 猿問(wèn) 以下內(nèi)容是關(guān)于C++面向?qū)ο蟪绦蛟O(shè)...

以下內(nèi)容是關(guān)于C++面向?qū)ο蟪绦蛟O(shè)計(jì)問(wèn)題，求解釋~

C++ C

寶慕林4294392 2021-11-20 15:11:17

題目：應(yīng)用VC++6.0的編輯環(huán)境構(gòu)造一個(gè)類(lèi)Jhtx及其派生類(lèi)，該類(lèi)主要實(shí)現(xiàn)關(guān)于幾何圖形的基本操作。對(duì)于基類(lèi)“幾何圖形”，有求面積、求體積的函數(shù)（純虛函數(shù)），其派生類(lèi)圓和矩形主要有初始化（構(gòu)造函數(shù)），求面積，求周長(zhǎng)操作，類(lèi)圓的派生類(lèi)圓球和圓柱有求表面積、體積操作。試在主函數(shù)中分別定義圓、圓球、圓柱以及矩形的對(duì)象，并調(diào)用其成員函數(shù)實(shí)現(xiàn)其相應(yīng)操作。以下是我的程序，但是有一些錯(cuò)誤，都是相同的錯(cuò)誤，請(qǐng)大家指教。#include<iostream.h>class Geometry{public:Geometry(double a,double b,double c){x=a,y=b,c=z;}~Geometry(){};virtual double GetArea()=0;double GetPerimeter();virtual double GetColume()=0;virtual void Show()=0;protected:double x,y,z;};class Circle:public Geometry{protected:double r;public:Circle(double a):Geometry(a,0,0){r=a;}~Circle(){};double GetArea(){return 3.14*r*r;} double GetPerimeter(){return 6.28*r;}virtual double GetColume(){return 0;}void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Perimeter is:"<<GetPerimeter()<<endl;} };class Rectangle:public Geometry{public: Rectangle(double a,double b):Geometry(a,b,0){}~Rectangle(){};double GetArea(){return x*y;}double GetPerimeter(){return x+y;} virtual double Getolume(){return 0;}void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Perimeter is:"<<GetPerimeter()<<endl;}};class Ball:public Circle{public: Ball(double a):Circle(a){};~Ball(){};double GetArea(){return 4*3.14*x*x;}double GetColume(){return (4/3)*3.14*x*x*x;}double GetPerimeter(){return 0;}void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Getcolume is:"<<GetColume()<<endl;}};class Column:public Circle{protected:double h;Column(double a,double h):Circle(a),h(h){}~Column(){};double GetArea(){return 2*3.14*x*x+2*3.14*x*h;}double GetColume(){return 3.14*x*x*h;}double GetPerimeter(){return 0;} void Show(){cout<<"Area is:"<<GetArea()<<endl;cout<<"Getcolume is:"<<GetColume()<<endl;}};int main(){ Geometry *p;Circle ob1(1);Rectangle ob2(2,2);Ball ob3(3);Column ob4(4,3);p=&ob1;p->GetArea();p->GetPerimeter();p->Show();p=&ob2;p->GetArea();p->GetPerimeter();p->Show();p=&ob3;p->GetArea();p->GetPerimeter();p->Show();p=&ob4;p->GetArea();p->GetPerimeter();p->Show();return 0;}

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2 回答

MYYA

TA貢獻(xiàn)1868條經(jīng)驗(yàn) 獲得超4個(gè)贊

我改了一下，已經(jīng)能通過(guò)并且運(yùn)行了：
#include<iostream.h>
class Geometry{
public:
Geometry(double a,double b,double c)
{x=a,y=b,c=z;}
~Geometry(){};
virtual double GetArea()=0;
virtual double GetPerimeter()=0;//這里有改動(dòng)
virtual double GetColume()=0;
virtual void Show()=0;
protected:
double x,y,z;
};
class Circle:public Geometry{
protected:
double r;
public:
Circle(double a):Geometry(a,0,0)
{r=a;}
~Circle(){};
double GetArea()
{return 3.14*r*r;}
double GetPerimeter()
{return 6.28*r;}
virtual double GetColume()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Perimeter is:"<<GetPerimeter()<<endl;}
};
class Rectangle:public Geometry{
public:
Rectangle(double a,double b):Geometry(a,b,0)
{}
~Rectangle(){};
double GetArea()
{return x*y;}
double GetPerimeter()
{return x+y;}
virtual double GetColume()//這里有改動(dòng)
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Perimeter is:"<<GetPerimeter()<<endl;}
};
class Ball:public Circle{
public:
Ball(double a):Circle(a)
{};
~Ball(){};
double GetArea()
{return 4*3.14*x*x;}
double GetColume()
{return (4/3)*3.14*x*x*x;}
double GetPerimeter()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Getcolume is:"<<GetColume()<<endl;}
};
class Column:public Circle{
public://這里改為public
double h;
Column(double a,double h):Circle(a),h(h){}
~Column(){};
double GetArea()
{return 2*3.14*x*x+2*3.14*x*h;}
double GetColume()
{return 3.14*x*x*h;}
double GetPerimeter()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Getcolume is:"<<GetColume()<<endl;}
};
int main()
{ Geometry *p;
Circle ob1(1);
Rectangle ob2(2,2);
Ball ob3(3);
Column ob4(4,3);
p=&ob1;
p->GetArea();
p->GetPerimeter();
p->Show();
p=&ob2;
p->GetArea();
p->GetPerimeter();
p->Show();
p=&ob3;
p->GetArea();
p->GetPerimeter();
p->Show();
p=&ob4;
p->GetArea();
p->GetPerimeter();
p->Show();
return 0;
}

反對(duì) 回復(fù) 2021-11-24

慕桂英4014372

TA貢獻(xiàn)1871條經(jīng)驗(yàn) 獲得超13個(gè)贊

#include<iostream>
using namespace std;

class Geometry{
public:
Geometry(double a,double b,double c)
{x=a,y=b,c=z;}
virtual ~Geometry(){};
virtual double GetArea()=0;
virtual double GetPerimeter()=0;
virtual double GetColume()=0;
virtual void Show()=0;
protected:
double x,y,z;
};
class Circle:public Geometry{
protected:
double r;
public:
Circle(double a):Geometry(a,0,0)
{r=a;}
virtual ~Circle(){};
double GetArea()
{return 3.14*r*r;}
double GetPerimeter()
{return 6.28*r;}
virtual double GetColume()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Perimeter is:"<<GetPerimeter()<<endl;}
};
class Rectangle:public Geometry{
public:
Rectangle(double a,double b):Geometry(a,b,0)
{}
~Rectangle(){};
double GetArea()
{return x*y;}
double GetPerimeter()
{return x+y;}
virtual double GetColume()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Perimeter is:"<<GetPerimeter()<<endl;}
};
class Ball:public Circle{
public:
Ball(double a):Circle(a)
{};
~Ball(){};
double GetArea()
{return 4*3.14*x*x;}
double GetColume()
{return (4/3)*3.14*x*x*x;}
double GetPerimeter()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Getcolume is:"<<GetColume()<<endl;}
};
class Column:public Circle{
public:
double h;
Column(double a,double h):Circle(a){
this->h = h;
}
~Column(){};
double GetArea()
{return 2*3.14*x*x+2*3.14*x*h;}
double GetColume()
{return 3.14*x*x*h;}
double GetPerimeter()
{return 0;}
void Show()
{cout<<"Area is:"<<GetArea()<<endl;
cout<<"Getcolume is:"<<GetColume()<<endl;}
};
int main()
{ Geometry *p;
Circle ob1(1);
Rectangle ob2(2,2);
Ball ob3(3);
Column ob4(4,3);
p=&ob1;
p->GetArea();
p->GetPerimeter();
p->Show();
p=&ob2;
p->GetArea();
p->GetPerimeter();
p->Show();
p=&ob3;
p->GetArea();
p->GetPerimeter();
p->Show();
p=&ob4;
p->GetArea();
p->GetPerimeter();
p->Show();
return 0;
}
改完了，能運(yùn)行，自己看看