如何將這個數(shù)組組合成一個字符串？array([' HHHHHHH HHHHHHHHHHH HHHHHHHHHHHHHHHHHHH ', ' E E EEE ', ' TT ', ' CC CCCC'])結(jié)果應(yīng)如下所示： result = 'EHHHHHHHEHHHHHHHHHHHTTCCEEEHHHHHHHHHHHHHHHHHHHCCCC'
3 回答
料青山看我應(yīng)如是
TA貢獻1772條經(jīng)驗 獲得超8個贊
一種快速的方法是使用zip逐個字符處理，并在每個位置取最大值；
arr = [' HHHHHHH HHHHHHHHHHH HHHHHHHHHHHHHHHHHHH ',
' E E EEE ',
' TT ',
' CC CCCC']
''.join(max(x) for x in zip(*arr))
' EHHHHHHHEHHHHHHHHHHHTTCCEEEHHHHHHHHHHHHHHHHHHHCCCC'
慕村225694
TA貢獻1880條經(jīng)驗 獲得超4個贊
像這樣的東西？
array =[' HHHHHHH HHHHHHHHHHH HHHHHHHHHHHHHHHHHHH ',
' E E EEE ',
' TT ',
' CC CCCC']
result = []
for pos in zip(*array): # create tuples of chars from the same index in all strings
char = ''.join(pos).replace(' ', '') # remove all space chars
if char: # if there's anything left (ie. skip the char at index 0)
result.append(char[-1]) # then append the char from the array closest to the bottom
result = ''.join(result) # convert back to string
print result
哪個打印
EHHHHHHHEHHHHHHHHHHHTTCCEEEHHHHHHHHHHHHHHHHHHHCCCC
慕森王
TA貢獻1777條經(jīng)驗 獲得超3個贊
這是一個numpy的解決方案：
>>> x
array([' HHHHHHH HHHHHHHHHHH HHHHHHHHHHHHHHHHHHH ',
' E E EEE ',
' TT ',
' CC CCCC'],
dtype='<U51')
>>> x.view('u4').reshape(len(x), -1).max(0).view(x.dtype).item(0).strip()
'EHHHHHHHEHHHHHHHHHHHTTCCEEEHHHHHHHHHHHHHHHHHHHCCCC'
時間：
f_pp 5.941 us
f_tb 27.473 us
f_ji 21.265 us
產(chǎn)生計時的代碼：
import numpy as np
from timeit import timeit
x = np.array([' HHHHHHH HHHHHHHHHHH HHHHHHHHHHHHHHHHHHH ',
' E E EEE ',
' TT ',
' CC CCCC'])
def f_pp():
return x.view('u4').reshape(len(x), -1).max(0).view(x.dtype).item(0).strip()
def f_tb():
result = []
for pos in zip(*x): # create tuples of chars from the same index in all string
char = ''.join(pos).replace(' ', '') # remove all space chars
if char: # if there's anything left (ie. skip the char at index 0)
result.append(char[-1]) # then append the char from the array closest to the bottom
return ''.join(result) # convert back to string
def f_ji():
return ''.join(max(y) for y in zip(*x)).strip()
for f in (f_pp, f_tb, f_ji):
print(f.__name__, f'{timeit(f, number=1000) * 1000:>6.3f} us')
添加回答
舉報
0/150
提交
取消