我正在做一個(gè)游戲。這個(gè)游戲是自上而下的，實(shí)時(shí)的，并且必須具有路徑。我的游戲必須計(jì)算玩家當(dāng)前位置與他們點(diǎn)擊步行到達(dá)的位置之間的角度。問題是，我正在使用屏幕坐標(biāo)，如“x 向右增加，y 向底部增加”這是我使用一些代碼的地方package mainimport (  "fmt"  "math")func main() {  position1 := &Position{550, 200}  position2 := &Position{700, 500}  vector1 := CreatePathVector(position1, position2, 50)  fmt.Printf("position1: %v\nposition2: %v\n", position1, position2)  position := position1  for i := 0; i < 5; i++ {    position = position.Add(vector1)    fmt.Printf("next position: %v\n", position)  }  position3 := &Position{400, 500}  position4 := &Position{700, 400}  vector2 := CreatePathVector(position3, position4, 50)  fmt.Printf("position3: %v\nposition4: %v\n", position3, position4)  position = position3  for i := 0; i < 5; i++ {    position = position.Add(vector2)    fmt.Printf("next position: %v\n", position)  }}type Position struct {  X float64  Y float64}type Vector struct {  Radians  float64  Distance float64}func CreatePathVector(pos1 *Position, pos2 *Position, speed int) *Vector {  ydiff := pos2.Y - pos1.Y  xdiff := pos2.X - pos1.X  radians := math.Atan2(ydiff, xdiff)  return &Vector{    Radians:  radians,    Distance: float64(speed),  }}func (p *Position) Add(v *Vector) *Position {  return &Position{    X: p.X + math.Sin(v.Radians)*v.Distance,    Y: p.Y + math.Cos(v.Radians)*v.Distance,  }}這是輸出position1: &{550 200}position2: &{700 500}next position: &{594.7213595499958 222.3606797749979}next position: &{639.4427190999916 244.72135954999578}next position: &{684.1640786499873 267.0820393249937}next position: &{728.8854381999831 289.44271909999156}next position: &{773.6067977499789 311.80339887498945}position3: &{400 500}position4: &{700 400}next position: &{384.1886116991581 547.4341649025257}next position: &{368.37722339831623 594.8683298050514}next position: &{352.56583509747435 642.3024947075771}next position: &{336.75444679663246 689.7366596101028}next position: &{320.9430584957906 737.1708245126285}如您所見，在兩個(gè)示例中，重復(fù)添加向量的步驟并沒有轉(zhuǎn)向目的地