如何在不刪除元組的情況下展平包含元組的嵌套列表？例子：flatten([1,2,3,(4,5,6),[7,8,9]]) [1, 2, 3, (4, 5, 6),7,8,9]
3 回答
絕地?zé)o雙
TA貢獻(xiàn)1946條經(jīng)驗 獲得超4個贊
為什么不是簡單的循環(huán)：
>>> L = [1,2,3,(4,5,6),[7,8,9]]
>>> L2 = []
>>> for i in L:
if isinstance(i,list):
L2.extend(i)
else:
L2.append(i)
>>> L2
[1, 2, 3, (4, 5, 6), 7, 8, 9]
>>>
嗶嗶one
TA貢獻(xiàn)1854條經(jīng)驗 獲得超8個贊
def flatten(arr):
if not isinstance(arr, list):
return arr
else:
output = []
for sy in arr:
if isinstance(sy, list):
temp = flatten(sy)
for py in temp:
output.append(py)
else:
output.append(sy)
return output
print (flatten([1,2,3,(4,5,6),[7,8,9]]))
#[1, 2, 3, (4, 5, 6), 7, 8, 9]
月關(guān)寶盒
TA貢獻(xiàn)1772條經(jīng)驗 獲得超5個贊
試試看：
f = lambda *n: (e for a in n
for e in (f(*a) if isinstance(a, (list)) else (a,)))
print(list(f([1,2,3,(4,5,6),[7,8,9]])))
# [1, 2, 3, (4, 5, 6), 7, 8, 9]
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