我是一名非常喜歡編程的本科生。我在做練習(xí)的時(shí)候遇到了一個(gè)問題，我很困惑。我在網(wǎng)上搜索了相關(guān)文件（https://www.dreamincode.net/forums/topic/293449-simple-pig-latin-program-have-trouble/），但我還不能清楚地理解。要求如下：給定一個(gè)空格分隔的單詞序列，返回一個(gè)新的空格分隔的單詞序列，修改為豬拉丁語。這里的豬拉丁語定義為修改一個(gè)單詞以去掉單詞第一個(gè)元音之前的字母，并在其末尾添加“ay”。如果單詞以元音開頭（a、e、i、o 或 u，而不是 y），只需在其末尾添加“way”即可。例如：ball 變成 allbay 而 I 變成 Iway。提示： split() 和 join() 函數(shù)在這里可能很有用。Example: Input: "this is a test" Output: "isthay isway away esttay" Example 2: Input: "how are you today" Output: "owhay areway ouyay odaytay"我的代碼如下：def pig_latin(s): VOWELS = ("a", "e", "i", "o", "u", "A", "E", "I", "O", "U") words = s.split() s1 = '' s2 = '' for w in words: if w[0] in VOWELS: s1 += w + 'ay' else: s2 += w[1:] + w[0] + 'ay' return s1.join(s2)測(cè)試用例如下：Traceback (most recent call last): File "/grade/run/test.py", line 40, in test_hard self.assertEqual(pig_latin(n), a)AssertionError: 'hriscaylustercayhrowtay' != 'ischray usterclay owthray'- hriscaylustercayhrowtay? -- ^ ^^+ ischray usterclay owthray? ++ ^ + ^ ++也Traceback (most recent call last): File "/grade/run/test.py", line 33, in test_case self.assertEqual(pig_latin(n), a)AssertionError: 'hisayaayofayiisayaayofaysisayaayofaytisay[472 chars]fayy' != 'isthay isway away ongerlay entencesay ofw[20 chars]yday'- hisayaayofayiisayaayofaysisayaayofaytisayaayofayaisayaayofayyisayaayofayoisayaayofaynisayaayofaygisayaayofayeisayaayofayrisayaayofaylisayaayofayaisayaayofayyisayaayofayeisayaayofaynisayaayofaytisayaayofayeisayaayofaynisayaayofaycisayaayofayeisayaayofaysisayaayofayaisayaayofayyisayaayofayeisayaayofaydisayaayofayiisayaayofayuisayaayofaymisayaayofaymisayaayofayaisayaayofayyisayaayofayiisayaayofayfisayaayofayfisayaayofayiisayaayofaycisayaayofayuisayaayofaylisayaayofaytisayaayofayyisayaayofaydisayaayofayaisayaayofayy+ isthay isway away ongerlay entencesay ofway ediummay ifficultyday我很困惑，謝謝大家的幫助。
2 回答
揚(yáng)帆大魚
TA貢獻(xiàn)1799條經(jīng)驗(yàn) 獲得超9個(gè)贊
此類問題應(yīng)首先正確解釋，然后使用筆和紙，嘗試設(shè)計(jì)一種算法來解決您的問題。然后，您可以對(duì)其進(jìn)行編碼，從而生成無錯(cuò)誤且功能齊全的代碼。這是您解決問題的代碼。
def fun(s):
words = s.split()
new_string = ""
vowels = ("a", "e", "i", "o", "u", "A", "E", "I", "O", "U")
for word in words:
new_word = ""
flag = False
for i in range(len(word)):
if word[i] in vowels and i>0:
new_word = word[i:] + word[:i] + "ay"
flag = True
break
if word[i] in vowels and i == 0:
new_word = word + "way"
break
if new_word:
new_string += " " + new_word
else:
new_string += " " + word
return new_string
測(cè)試用例：
>>> fun("this is a test")
' isthay isway away esttay'
>>> fun("bcd")
' bcd'
>>> fun("how are you today")
' owhay areway ouyay odaytay'
料青山看我應(yīng)如是
TA貢獻(xiàn)1772條經(jīng)驗(yàn) 獲得超8個(gè)贊
這就是你的函數(shù)應(yīng)該是什么樣子
def pig_latin(s):
VOWELS = ("a", "e", "i", "o", "u", "A", "E", "I", "O", "U")
words = s.split()
result = []
for w in words:
if w[0] in VOWELS:
result.append(w + 'way')
else:
for idx, char in enumerate(w):
if char in VOWELS:
result.append(w[idx:] + w[:idx] + 'ay')
break
else:
continue
else:
result.append(w)
return ' '.join(result)
由于您想取出第一個(gè)元音之前的所有輔音，您需要遍歷每個(gè)單詞以檢查第一個(gè)元音的位置。
此外，在執(zhí)行 時(shí)s1.join(s2)，您會(huì)忘記在單詞之間添加額外的空格。
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