2 回答

TA貢獻(xiàn)1862條經(jīng)驗(yàn) 獲得超6個(gè)贊
如果性能不是問題,那么您可以執(zhí)行以下操作,
import java.io.File;
import java.util.List;
import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import org.w3c.dom.Document;
import org.w3c.dom.NodeList;
public class ReadFiles {
public static void main(String[] args) {
File dir = new File("D:/Work"); //Directory where your file exists
File [] files = dir.listFiles();
for(File file : files) {
if(file.isFile() && file.getName().endsWith(".xml")) { //You can validate file name with extension if needed
ProcessFile(file, Entities); // Assumed you have declared Entities, may be list of other collection
}
}
System.out.println(Entities);
}
private static void ProcessFile(File fXmlFile, List<E> Entities) {
try {
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nList = doc.getElementsByTagName("sindex");
System.out.println("----------------------------");
for (int temp = 0; temp < nList.getLength(); temp++) {
Node nNode = nList.item(temp);
System.out.println("");
if (nNode.getNodeType() == Node.ELEMENT_NODE) {
Element eElement = (Element) nNode;
System.out.println("Name : " + eElement.getElementsByTagName("name").item(0).getTextContent());
System.out.println("Count : " + eElement.getElementsByTagName("count").item(0).getTextContent());
Entity CE = new Entity(eElement.getElementsByTagName("name").item(0).getTextContent(), Integer.parseInt(eElement.getElementsByTagName("count").item(0).getTextContent()));
Entities.add(CE);
System.out.println("Entity added! ");
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
}

TA貢獻(xiàn)1863條經(jīng)驗(yàn) 獲得超2個(gè)贊
要讀取多個(gè)文件,您應(yīng)該使用某種循環(huán)進(jìn)行迭代。您可以掃描目錄中的所有有效文件。
File folder = new File("path/to/directory");
File[] files = folder.listFiles();
for (int i = 0; i < files.length; i++) {
// you can also filter for .xml if needed
if (files[i].isFile()) {
// parse the file
}
}
接下來,您需要決定如何解析文件:順序或并行。由于您使用多個(gè)線程來解析文件,因此 Parallel 會(huì)快很多。
一根線
您可以重用您已經(jīng)編寫的代碼,并遍歷文件:
for (File file : files) {
processFile(file, yourListOfEntities);
}
多線程:
獲取一個(gè)ScheduledExecutorService并提交多個(gè)任務(wù)。
ExecutorService service = Executors.newFixedThreadPool(5);
for (File file : files) {
service.execute(() -> processFile(file, yourListOfEntities));
}
這里有一個(gè)重要的注意事項(xiàng): 的默認(rèn)實(shí)現(xiàn)ArrayList不是線程安全的,所以你應(yīng)該(因?yàn)長(zhǎng)ist被多個(gè)線程使用)同步對(duì)它的訪問:
List<Entity> synchronizedList = Collections.synchronizedList(yourListOfEntities);
此外,DocumentBuilder不是線程安全的,應(yīng)該為每個(gè)線程創(chuàng)建一次(如果你只是調(diào)用你的方法,你就對(duì)了)。如果您考慮優(yōu)化它,則此注釋僅適用于這種情況。
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