我正處于嘗試圍繞 Go 進(jìn)行思考的嬰兒階段。目前，我正在模擬一個 API 請求，該請求返回一個包含對象數(shù)組的 JSON 格式的字符串。我試圖找出最合適的方法來迭代每個記錄并訪問每個字段。最終，每個字段都將寫入 Excel 電子表格，但現(xiàn)在我只想打印每個字段的鍵和值。這是我所擁有的（我會在 Go Playground 中提供它，但不支持 HTTP 請求）： response, err := http.Get("http://go-proto.robwilkerson.org/demo.json") failOnError(err, "Uh oh") defer response.Body.Close() var view []interface{} json.NewDecoder(response.Body).Decode(&view) log.Printf(" [x] Pulled JSON: %s", view) for _, record := range view { log.Printf(" [===>] Record: %s", record) for key, val := range record { log.Printf(" [========>] %s = %s", key, val) } }一切正常，直到嵌套循環(huán)嘗試迭代map保存每條記錄的屬性：cannot range over record (type interface {})我有兩個問題，我想：嵌套循環(huán)是訪問每條記錄的每個屬性的最有效/最高效的方法嗎？我需要做什么來解決這個錯誤？更新當(dāng)我將解碼的數(shù)據(jù)轉(zhuǎn)儲到view變量中時，這是記錄的結(jié)果：[ map[id:ef14912f-8031-42b3-8c50-7aa612287534 avatar:http://placehold.it/32x32 name:Vilma Hobbs email:vilmahobbs@exiand.com phone:+1 (886) 549-3522 address:471 Dahill Road, Jacksonwald, Alabama, 6026] map[id:1b7bf182-2482-4b8b-8210-9dc9ee51069e avatar:http://placehold.it/32x32 name:Anne Dalton email:annedalton@exiand.com phone:+1 (994) 583-2947 address:660 Macdougal Street, Ticonderoga, Alaska, 7942] map[id:f8027852-f52e-4bbb-bc9d-fb5e34929b40 avatar:http://placehold.it/32x32 name:Amie Ray email:amieray@exiand.com phone:+1 (853) 508-3649 address:878 Kane Street, Derwood, Minnesota, 3826] map[id:b9842ab7-5053-48b4-a991-f5c63af8fb7e avatar:http://placehold.it/32x32 name:Hope Benton email:hopebenton@exiand.com phone:+1 (938) 542-2232 address:396 Osborn Street, Rowe, Massachusetts, 702] map[id:8f9f6d8d-d14e-4ddc-acb2-eb96d3c3d7a8 avatar:http://placehold.it/32x32 name:Janine Kidd email:janinekidd@exiand.com phone:+1 (877) 474-2633 address:173 Manhattan Court, Hall, Virginia, 7376] map[avatar:http://placehold.it/32x32 name:Kristen Yang email:kristenyang@exiand.com phone:+1 (862) 469-3446 address:203 Doughty Street, Westmoreland, Rhode Island, 849 id:210a6ae6-8227-4f26-a47c-448c400f26e9] ]
1 回答
RISEBY
TA貢獻(xiàn)1856條經(jīng)驗 獲得超5個贊
未聲明類型時 json 包將解碼為的默認(rèn)值是：
bool, for JSON booleans
float64, for JSON numbers
string, for JSON strings
[]interface{}, for JSON arrays
map[string]interface{}, for JSON objects
nil for JSON null
由于每個record（在您的示例中）都是一個 json 對象，因此您可以map[string]interface{}像這樣斷言每個對象：
for _, record := range view {
log.Printf(" [===>] Record: %s", record)
if rec, ok := record.(map[string]interface{}); ok {
for key, val := range rec {
log.Printf(" [========>] %s = %s", key, val)
}
} else {
fmt.Printf("record not a map[string]interface{}: %v\n", record)
}
}
- 1 回答
- 0 關(guān)注
- 869 瀏覽
添加回答
舉報
0/150
提交
取消