2 回答
TA貢獻1847條經(jīng)驗 獲得超11個贊
var result = dt.AsEnumerable()
.GroupBy(d => d.Field<string>("Class"))
.Select(g => new
{
Name = string.Join(",",
g.Select(gn => gn.Field<string>("Name")).Distinct()),
Class = g.Key,
Teacher = string.Join(",",
g.Select(gt => gt.Field<string>("Ability")).Distinct())
});
注意:如果您直接使用 Linq 而不是 DataTable,這會容易得多。
TA貢獻1825條經(jīng)驗 獲得超4個贊
我為樣本創(chuàng)建了一個虛擬數(shù)據(jù)
DataTable dtNew, dt = new DataTable();
dt.Columns.Add("Id", typeof(string));
dt.Columns.Add("Category",typeof(string));
dt.Columns.Add("Type",typeof(string));
dtNew = dt.Clone();
dt.Rows.Add("323021", "Doors", "900");
dt.Rows.Add("323022", "Doors", "900");
dt.Rows.Add("323023", "Doors", "1000");
dt.Rows.Add("323024", "Doors", "1000");
dt.Rows.Add("323025", "Walls", "200");
dt.Rows.Add("323026", "Walls", "200");
dt.Rows.Add("323027", "Walls", "200");
dt.Rows.Add("323028", "Walls", "200");
dt.Rows.Add("323026", "Columns", "300x300");
dt.Rows.Add("323027", "Columns", "300x300");
dt.Rows.Add("323028", "Columns", "500x500");
此場景的解決方案
//Case 1: Category and Type
var caretoryTypeResult = (from b in dt.AsEnumerable()
group b by new
{
Category = b.Field<string>("Category"),
Type = b.Field<string>("Type")
}
into grpCategoryType
select new
{
grpCategoryType.Key.Category,
grpCategoryType.Key.Type,
grpCategoryType
}).ToList();
caretoryTypeResult.ForEach(list => {
var category = list.grpCategoryType.AsEnumerable().Select(m => m.Field<string>("Id")).ToList();
dtNew.Rows.Add(string.Join(",", category), list.Category, list.Type);
});
希望這段代碼有幫助
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