#include "iostream"using namespace std;class simplecat{public:simplecat(int age,int weight){itsage=age; itsweight=weight;}~simplecat(){cout<<" destructor "<<endl;}int getage() const {return itsage;}int getweight() const {return itsweight;}private:int itsage;int itsweight;};simplecat & thefunction(){simplecat * p = new simplecat (5,9);cout<<p<<endl;return *p;}void main(){simplecat & rcat= thefunction();int age=rcat.getage();cout<<"rcat is "<<rcat.getage ()<<" years old"<<endl;} 書上對(duì)于釋放的方法說了三種，可是我沒看懂，幫是說下這三中方法是怎么做的。1、main函數(shù)里的第一行聲明一個(gè) simplecat 對(duì)象，然后從函數(shù) thefunction（）按值返回該對(duì)象2、仍是在 thefunction（） 中聲明一個(gè)自由存儲(chǔ)區(qū)的simple，但是讓函數(shù)thefunction（）返回 一個(gè)指向該對(duì)象的指針。這樣使用完該對(duì)象后，調(diào)用函數(shù)可將該指針刪除3、在調(diào)用函數(shù)中聲明對(duì)象，然后按引用將它傳遞給函數(shù)thefunction（）
1 回答
Helenr
TA貢獻(xiàn)1780條經(jīng)驗(yàn) 獲得超4個(gè)贊
用delete就可以了 只要給出了分配內(nèi)存的首地址就可以了釋放代碼如下 如果我的回答讓你滿意的話 請(qǐng)選為滿意答案哦#include "iostream"
using namespace std;
class simplecat
{
public:
simplecat(int age,int weight){itsage=age; itsweight=weight;}
~simplecat(){cout<<" destructor "<<endl;}
int getage() const {return itsage;}
int getweight() const {return itsweight;}
private:
int itsage;
int itsweight;
};simplecat & thefunction()
{
simplecat * p = new simplecat (5,9);
cout<<p<<endl;
return *p;
}void main()
{
simplecat & rcat= thefunction();
int age=rcat.getage();cout<<"rcat is "<<rcat.getage ()<<" years old"<<endl;
delete &rcat;
}
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