我的代碼目前非常簡單#BlackJackprint("welcome to Wasteful's blackjack game")`print("this program was built using standard python")print("please select a option")print("A to start, B to quit")print("----------------------------")menu_select = input("A/B: ").lowerif menu_select == "a": print("starting game when i can be assed to program it")elif menu_select == "b": exit()else: print("invalid")但它對兩者a和b?都返回空白？我被卡住了，可以使用一些幫助，謝謝！編輯：我注意到 .lower 中的愚蠢錯誤應該是 .lower()
2 回答
精慕HU
TA貢獻1845條經(jīng)驗 獲得超8個贊
def main():
print("welcome to Wasteful's blackjack game")
print("this program was built using standard python")
print("please select a option")
print("A to start, B to quit")
print("----------------------------")
menu_select = input("A/B: ").lower()
if (menu_select == "a"):
print("starting game when i can be assed to program it")
elif (menu_select == "b"):
exit()
else:
print("invalid")
main()
首先就像 rassar 說的，你必須在你從用戶那里得到你的輸入之后調(diào)用 .lower() 。接下來，我總是發(fā)現(xiàn)創(chuàng)建一個主循環(huán)函數(shù)來調(diào)用所有未來的函數(shù)并保持代碼漂亮整潔更容易！希望這會有所幫助！快樂編碼！:)
楊__羊羊
TA貢獻1943條經(jīng)驗 獲得超7個贊
這是因為你不打電話lower()，你設置menu_select的函數(shù)本身：
>>> menu_select = input("? ").lower
?
>>> menu_select
<built-in method lower of str object at 0x10ca5eab0>
將您的線路更改為：
menu_select = input("A/B: ").lower()
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