我有幾個(gè)字符串需要循環(huán)并執(zhí)行一些操作，以便在某些迭代后返回原始字符串。例如在 string "1010"，在每次迭代中，我需要根據(jù)迭代次數(shù)移動(dòng)前面的字符First iteration (1 iteration):  0101   (moved 1 character from front)Second iteration (2 iteration): 0101   (moved 2 characters from front)Third iteration (3 iteration):  1010   (moved 3 characters from front)所以我找回了原來(lái)的字符串但是對(duì)于像 那樣的字符串"1001"，它將需要 7 次迭代First iteration (1 iteration): 0011   (moved 1 character from front)Second iteration (2 iteration): 1100   (moved 2 characters from front)Third iteration (3 iteration): 0110   (moved 3 characters from front)Fourth iteration (4 iteration): 0110   (moved 4 characters from front)Fifth iteration (5 iteration): 1100   (moved 5 characters from front)Sixth iteration (6 iteration): 0011   (moved 6 characters from front)Seventh iteration (7 iteration): 1001   (moved 7 characters from front)下面是我的代碼string_list = ["1010", "1001"]for i in string_list:    print("i",i)    t = 1    print("starting t",t)    new_string = i    for j in i:        num_letter = new_string[:t]        print("num_letter", num_letter)        new_string = new_string[t:] + num_letter        print("intermediate new string",new_string)        if new_string == i:            print("no of iterations until same string occurs", t)            break        else:            t += 1            print("t",t)對(duì)于第一個(gè)字符串，我沒有得到3正確的迭代。但是對(duì)于第二個(gè)字符串，它在第五次迭代時(shí)停止，因?yàn)樽址拈L(zhǎng)度被完全覆蓋。我如何確保它一直循環(huán)遍歷字符串，直到我得到一個(gè)與原始字符串相同的字符串？