我有 2 個(gè) StructuredNodesUser并且Token是一對一的關(guān)系。來自將 Django 用于關(guān)系數(shù)據(jù)庫，如果我想給用戶一個(gè)令牌，我只會(huì)做User.objects.get(token__key=token).但是使用 Neo4j 和 NeoModel，我正在努力尋找一種方法來執(zhí)行這個(gè)簡單的查詢。我必須為此使用密碼嗎？如果是這樣怎么辦？此外，當(dāng)我擁有User實(shí)例時(shí)，我可以user.token.single()獲取Token實(shí)例，但反過來就行不通了。token.user.single()返回CardinalityViolation: Expected: one relationship in a outgoing direction of type FOR_USER on node (49) of class 'Token', got: none.和 token.user 返回一個(gè)neomodel.cardinality.One對象。class User(DjangoNode):    uid = UniqueIdProperty()    firstname = StringProperty(index=True, required=True)    lastname = StringProperty(index=True, required=True)    email = EmailProperty(unique_index=True, required=True)    password = StringProperty(requried=True)    token = RelationshipFrom('Token', 'OWNS_TOKEN', cardinality=One)    def post_create(self):        token = Token().save()        self.token.connect(token)class Token(DjangoNode):    user = RelationshipTo('Token', 'FOR_USER', cardinality=One)    key = StringProperty(unique_index=True, default=generate_key)    created = DateTimeProperty(default_now=True)