我有兩個(gè)列表是old_list = [{"tag": "apple","value":4}, {"tag": "orange","value":5}]new_list = [{"tag": "apple","value":1}, {"tag": "orange","value":2}, {"tag": "grape","value":3}]我想要一個(gè)new_list，如果 new_listitem['tag']等于 old_list item['tag']，則new_list['value']等于old_list['value']，如果 new_list 有新項(xiàng)目，則new_list['value']初始化 0。結(jié)果：new_list = [{"tag": "apple","value":4}, {"tag": "orange","value":5}, {"tag": "grape","value":0}]這是我的實(shí)現(xiàn)：old_list = [{"tag": "apple","value":4}, {"tag": "orange","value":5}]new_list = [{"tag": "apple","value":1}, {"tag": "orange","value":2}, {"tag": "grape","value":3}]update_list = []for new in new_list:    flag_new_item = True    for old in old_list:        if new["tag"] == old['tag']:            new["value"] = old['value']            flag_new_item = False            break    if flag_new_item:        new['value'] = 0print(new_list)因?yàn)槲沂褂?2' 次迭代器來實(shí)現(xiàn)這個(gè)問題，我認(rèn)為這太慢了，而且是非 Python 風(fēng)格，而且我引入了看起來不太好的新標(biāo)志。有沒有更直接、更方便、更有效的方式來實(shí)現(xiàn)它