我需要能夠準(zhǔn)確地找到兩個(gè)日期之間的月數(shù)，即使它們跨越不同的年份。我有從這個(gè)StackOverflow 線程獲得的以下解決方案，但它在日期跨越不同年份時(shí)失敗。當(dāng)它跨越一年時(shí)有效from datetime import datetimefrom dateutil.relativedelta import relativedeltadate1 = datetime.strptime('2010-01-01', '%Y-%m-%d')date2 = datetime.strptime('2010-12-01', '%Y-%m-%d')diff = relativedelta(date2, date1)number_of_months = diff.monthsprint(number_of_months) # 11當(dāng)它跨越多年時(shí)失敗from datetime import datetimefrom dateutil.relativedelta import relativedeltadate1 = datetime.strptime('2010-01-01', '%Y-%m-%d')date2 = datetime.strptime('2012-02-01', '%Y-%m-%d')diff = relativedelta(date2, date1)number_of_months = diff.monthsprint(number_of_months) # 1鑒于此，我考慮了以下解決方案：from datetime import datetimefrom dateutil.relativedelta import relativedeltadef month_diff(date1, date2):    if date1.year == date2.year:        diff = relativedelta(date2, date1)        number_of_months = diff.months    else:        num_of_days = (date2 - date1).days        number_of_months = num_of_days//30    print(number_of_months)date1 = datetime.strptime('2010-01-01', '%Y-%m-%d')date2 = datetime.strptime('2010-12-01', '%Y-%m-%d')date3 = datetime.strptime('2010-01-01', '%Y-%m-%d')date4 = datetime.strptime('2012-02-01', '%Y-%m-%d')month_diff(date1, date2) # 11month_diff(date3, date4)  # 25因此，我的問題是，是否有比我目前擁有的更好的解決方案？