我不知道這個問題的正確標(biāo)題。如果我沒有添加適當(dāng)?shù)臉?biāo)題，請幫我編輯這個問題。我正在嘗試為活動預(yù)訂大廳空間?？臻g預(yù)訂分為三種類型：Full - 0 (Can book by one team at same time)Half - 1 (Can book by 2 team at same time)Shared - 2 (Can book by 4 teams at same time)所以，我寫了下面提到的代碼。<?php $obj0 = new stdClass();$obj0->id = '1';$obj0->start = '2019-06-28';$obj0->end = '2019-06-28';$obj0->start_time = '07:00:00';$obj0->end_time = '08:00:00';$obj0->hall_space = '1';$obj1 = new stdClass();$obj1->id = '7';$obj1->start = '2019-06-28';$obj1->end = '2019-06-28';$obj1->start_time = '06:00:00';$obj1->end_time = '07:00:00';$obj1->hall_space = '1';$obj2 = new stdClass();$obj2->id = '2';$obj2->start = '2019-06-29';$obj2->end = '2019-06-29';$obj2->start_time = '07:00:00';$obj2->end_time = '08:00:00';$obj2->hall_space = '1';$obj3 = new stdClass();$obj3->id = '8';$obj3->start = '2019-06-29';$obj3->end = '2019-06-29';$obj3->start_time = '06:00:00';$obj3->end_time = '07:00:00';$obj3->hall_space = '1';$obj4 = new stdClass();$obj4->id = '3';$obj4->start = '2019-06-30';$obj4->end = '2019-06-30';$obj4->start_time = '07:00:00';$obj4->end_time = '08:00:00';$obj4->hall_space = '1';$obj5 = new stdClass();$obj5->id = '9';$obj5->start = '2019-06-30';$obj5->end = '2019-06-30';$obj5->start_time = '06:00:00';$obj5->end_time = '07:00:00';$obj5->hall_space = '1';$data = array($obj0, $obj1, $obj2, $obj3, $obj4, $obj5);$hall_space = 1; //this means user is trying to book half space這對于單個事件（即非重復(fù)）工作正常。但是，對于重復(fù)事件，這不能正常工作。在這里，在這種情況下，用戶試圖預(yù)訂半空間（即值 1）的日期2019-06-28to 2019-06-30from 6 am to 8am。上面提到的$data代表該時間范圍內(nèi)所有已預(yù)訂的事件，這意味著每天有兩個半間隔事件（一個從早上 6 點到 7 點，另一個從早上 7 點到 8 點）。這意味著應(yīng)該允許預(yù)訂這個新事件（半間隔）。但是，我的邏輯不起作用，因為它正在考慮所有這些事件，因為它們將在相同的日期和時間舉行。這意味著，$half僅當(dāng)事件發(fā)生在相同的日期和時間時才應(yīng)增加變量，并且最終不應(yīng)產(chǎn)生錯誤。我試圖從我的角度解釋所有內(nèi)容，您也可以復(fù)制并粘貼代碼進(jìn)行測試。如果您需要更多詳細(xì)信息，請告訴我。