我試圖在兩個(gè)詞之間找到一個(gè)子字符串，但我的起始詞包含一個(gè)撇號(hào)，我似乎無(wú)法匹配它。例如，在下面這句話中bus driver drove steady although the bus's steering was going nuts.我的搜索的正確答案應(yīng)該是：steering was going nuts并不是：driver ... nuts我試過(guò)這個(gè)re := regexp.MustCompile("(?s)bus[\\\'].*?nuts")我也試過(guò)這個(gè)：re := regexp.MustCompile("(?s)bus'.*?nuts")似乎無(wú)法讓它發(fā)揮作用。
2 回答
一只斗牛犬
TA貢獻(xiàn)1784條經(jīng)驗(yàn) 獲得超2個(gè)贊
您可以使用字符串文字（帶反引號(hào)）來(lái)包含單引號(hào)和捕獲組：
re := regexp.MustCompile(`(?s)bus'.\s+(.*?nuts)`)
看這個(gè)例子：
var source_txt = `bus driver drove steady although the bus's steering was going nuts.`
func main() {
fmt.Printf("Experiment with regular expressions.\n")
fmt.Printf("source text:\n")
fmt.Println("--------------------------------")
fmt.Printf("%s\n", source_txt)
fmt.Println("--------------------------------")
// a regular expression
regex := regexp.MustCompile(`(?s)bus'.\s+(.*?nuts)`)
fmt.Printf("regex: '%v'\n", regex)
matches := regex.FindStringSubmatch(source_txt)
for i, v := range matches {
fmt.Printf("match %2d: '%s'\n", i+1, v)
}
}
輸出：
Experiment with regular expressions.
source text:
--------------------------------
bus driver drove steady although the bus's steering was going nuts.
--------------------------------
regex: '(?s)bus'.\s+(.*?nuts)'
match 1: 'bus's steering was going nuts'
match 2: 'steering was going nuts'
的FindStringSubmatch()：
識(shí)別 s 中正則表達(dá)式最左邊的匹配項(xiàng)及其子表達(dá)式的匹配項(xiàng)（如果有）
這match[1]將是第一個(gè)捕獲組。
猛跑小豬
TA貢獻(xiàn)1858條經(jīng)驗(yàn) 獲得超8個(gè)贊
我的搜索的正確答案應(yīng)該是"steering was going nuts"......
如果您希望該子字符串作為您的匹配結(jié)果，您應(yīng)該相應(yīng)地調(diào)整您的正則表達(dá)式。
re := regexp.MustCompile("(?s)bus's (.*?nuts)")
rm := re.FindStringSubmatch(str)
if len(rm) != 0 {
fmt.Printf("%q\n", rm[0]) // "bus's steering was going nuts"
fmt.Printf("%q", rm[1]) // "steering was going nuts"
}
- 2 回答
- 0 關(guān)注
- 285 瀏覽
添加回答
舉報(bào)
0/150
提交
取消