我正在創(chuàng)建一個 API，但最終服務(wù)器以包含 RECORD 屬性的 JSON 格式向我發(fā)送信息：{ "RECORD": [{ "@ID": "1", "FULLNAME": "*\"* **** ****", "PHONE": "*******", "CELLULAR": "********", "LOGIN_STATUS": "*", "LOGIN_STATUS_TEXT": "****", "STUDENT_ACADEMIC_YEAR": "", "STUDENT_DEPARTMENT": "", "STUDENT_SPECIALITY": "", "STUDENT_PHONE": "", "STUDENT_CELLULARPHONE": "", "STUDENT_ADDRESS": " *", "STUDENT_EMAIL": "", "STUDENT_STATUS": "", "STUDENT_ID": "*", "TEACHER_ID": "*******", "CURRENTYEAR": "****", "TOKEN": "*************", "CURRENTFULLYEAR": "****" }]}如何從內(nèi)部屬性中提取數(shù)據(jù)？我使用以下命令解碼：$jsonRestData=json_decode($jsonRestData2, true);我試過了：$request_json["attributes"] = array( "userid" => str_replace(" ","",$user_uid), "fullname" => $jsonRestData->FULLNAME, "email" => $jsonRestData->STUDENT_EMAIL, "role" => $jsonRestData->STUDENT_STATUS, "year" => $jsonRestData->STUDENT_ACADEMIC_YEAR, "department" => $jsonRestData->STUDENT_DEPARTMENT, "speciality" => $jsonRestData->STUDENT_SPECIALITY ); 我也試過： $request_json["attributes"] = array( "userid" => str_replace(" ","",$user_uid), "fullname" => $jsonRestData->RECORD->FULLNAME, "email" => $jsonRestData->RECORD->STUDENT_EMAIL, "role" => $jsonRestData->RECORD->STUDENT_STATUS, "year" => $jsonRestData->RECORD->STUDENT_ACADEMIC_YEAR, "department" => $jsonRestData->RECORD->STUDENT_DEPARTMENT, "speciality" => $jsonRestData->RECORD->STUDENT_SPECIALITY );對于第一個示例，我收到一個錯誤：未定義的屬性：stdClass::$FULLNAME第二個我收到一個錯誤：試圖獲取非對象的屬性
3 回答
FFIVE
TA貢獻(xiàn)1797條經(jīng)驗(yàn) 獲得超6個贊
您的原始代碼（第二部分，帶有RECORD）只有一個問題：它假設(shè)RECORD是一個記錄。但顯然它是一個包含單個記錄的數(shù)組。
至于 put truein json_decode，有這么多上下文其實(shí)并不重要，因?yàn)闆]有給出明確的好處或壞處。但是如果你確實(shí)true在那里使用，你需要相應(yīng)地調(diào)整代碼，因?yàn)閠rue輸出是嵌套數(shù)組，但沒有它輸出是嵌套對象和數(shù)組。
這是一個示例 PHP，它展示了兩種方法——使用true和不使用它。
<?php
$jsonRestData2 = '{
"RECORD": [{
"@ID": "1",
"FULLNAME": "*\"* **** ****",
"PHONE": "*******",
"CELLULAR": "********",
"LOGIN_STATUS": "*",
"LOGIN_STATUS_TEXT": "****",
"STUDENT_ACADEMIC_YEAR": "",
"STUDENT_DEPARTMENT": "",
"STUDENT_SPECIALITY": "",
"STUDENT_PHONE": "",
"STUDENT_CELLULARPHONE": "",
"STUDENT_ADDRESS": " *",
"STUDENT_EMAIL": "",
"STUDENT_STATUS": "",
"STUDENT_ID": "*",
"TEACHER_ID": "*******",
"CURRENTYEAR": "****",
"TOKEN": "*************",
"CURRENTFULLYEAR": "****"
}]
}';
$jsonRestData = json_decode($jsonRestData2);
$request_json = [];
$request_json["attributes"] = array(
"fullname" => $jsonRestData->RECORD[0]->FULLNAME,
"email" => $jsonRestData->RECORD[0]->STUDENT_EMAIL,
"role" => $jsonRestData->RECORD[0]->STUDENT_STATUS,
"year" => $jsonRestData->RECORD[0]->STUDENT_ACADEMIC_YEAR,
"department" => $jsonRestData->RECORD[0]->STUDENT_DEPARTMENT,
"speciality" => $jsonRestData->RECORD[0]->STUDENT_SPECIALITY,
);
print_r($request_json);
$jsonRestData = json_decode($jsonRestData2, true);
$request_json = [];
$request_json["attributes"] = array(
"fullname" => $jsonRestData['RECORD'][0]['FULLNAME'],
"email" => $jsonRestData['RECORD'][0]['STUDENT_EMAIL'],
"role" => $jsonRestData['RECORD'][0]['STUDENT_STATUS'],
"year" => $jsonRestData['RECORD'][0]['STUDENT_ACADEMIC_YEAR'],
"department" => $jsonRestData['RECORD'][0]['STUDENT_DEPARTMENT'],
"speciality" => $jsonRestData['RECORD'][0]['STUDENT_SPECIALITY'],
);
print_r($request_json);
這是示例代碼輸出的內(nèi)容：
Array
(
[attributes] => Array
(
[fullname] => *"* **** ****
[email] =>
[role] =>
[year] =>
[department] =>
[speciality] =>
)
)
Array
(
[attributes] => Array
(
[fullname] => *"* **** ****
[email] =>
[role] =>
[year] =>
[department] =>
[speciality] =>
)
)
如您所見，輸出是相同的，即兩種方式都可以正常工作。
慕容3067478
TA貢獻(xiàn)1773條經(jīng)驗(yàn) 獲得超3個贊
你必須使用 $data = json_decode($jsondata, true);
之后，您可以將數(shù)據(jù)作為數(shù)組訪問
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