我在一個(gè) Andriod 應(yīng)用程序上工作。我從數(shù)據(jù)庫中讀取了一些字符串并在 ListView 中輸出它們。我的問題是，如果我在逐步模式下，來自 DB 的返回字符串運(yùn)行良好。如果我處于運(yùn)行模式，或者即使我將斷點(diǎn)放在收到結(jié)果的行之后。字符串變量將為空。 BackgroundWorker backgroundWorker = new BackgroundWorker( this); backgroundWorker.execute("Names"); res = backgroundWorker.FinalRes; res = res.replace("[",""); res = res.replace("]",""); res = res.replace("\"",""); ParsedStringsResult = PasrString(res); ArrayList<ListNames> NameSs= new ArrayList<ListNames>(); int size = ParsedStringsResult.length; for ( int i=0; i<size;i++ ) NameSs.add(new ListNames(ParsedStringsResult[i]));如果我把斷點(diǎn)放在 res=backgroundWorker.FinalRes;它運(yùn)行良好并顯示值如果我把它放在這一行之后甚至在默認(rèn)運(yùn)行模式下， res 將為空！為什么會(huì)發(fā)生這種情況，我該如何解決？我的背景課public class BackgroundWorker extends AsyncTask<String , Void, String> {Context context;public String FinalRes="";AlertDialog alertDialog;BackgroundWorker(Context ctx){    context = ctx;}@Overrideprotected String doInBackground(String... params) {    String type = params[0];    if (type == "Names") {        String url_login = "http://192.168.1.2/MyApp/getNames.php";        try {            URL url = new URL(url_login);            HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();            httpURLConnection.setRequestMethod("POST");            httpURLConnection.setDoOutput(true);            httpURLConnection.setDoInput(true);          /*  OutputStream outputStream = httpURLConnection.getOutputStream();            BufferedWriter bufferedWriter = new BufferedWriter(new OutputStreamWriter(outputStream, "UTF-8"));            String post_data = URLEncoder.encode("name", "UTF-8") + "=" + URLEncoder.encode(name, "UTF-8");// +"&"+ w nkml tany            bufferedWriter.write(post_data);            bufferedWriter.flush();            bufferedWriter.close();            outputStream.close();*/        }