lst = ['mylist1','mylist2','mylist3']for x in lst: for r in xrange(2): print x輸出：（重復(fù)列表中的元素兩次）[root@localhost ~]# python test.pymylist1mylist1mylist2mylist2mylist3mylist3如何隨機(jī)元素到：mylist3mylist1mylist3mylist2mylist2mylist1
2 回答
回首憶惘然
TA貢獻(xiàn)1847條經(jīng)驗(yàn) 獲得超11個(gè)贊
或*（乘法運(yùn)算符）：
lst = lst*2 # repeat items twice
shuffle(lst)
for x in lst:
print(x)
或者list comprehension：
lst = [x for i in range(2) for x in lst] # repeat items twice
shuffle(lst)
for x in lst:
print(x)
呼啦一陣風(fēng)
TA貢獻(xiàn)1802條經(jīng)驗(yàn) 獲得超6個(gè)贊
您可以首先使用 list 將列表中的每個(gè)元素加倍extend()，然后對列表進(jìn)行洗牌
from random import shuffle
lst = ['mylist1','mylist2','mylist3']
lst = lst.extend(lst) # repeat items twice
shuffle(lst)
for x in lst:
print(x)
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