我試圖在 Python 中使用命令 context.rotate(angle) 在 JS 中模擬一些可用的行為。我有以下代碼： import pygame import math import numpy as nppygame.init()CLOCK = pygame.time.Clock()RED = pygame.color.THECOLORS['red']WHITE = pygame.color.THECOLORS['white']screen = pygame.display.set_mode((0, 0), pygame.FULLSCREEN)screen_width, screen_height = screen.get_size()surface = pygame.Surface((50, 50), pygame.SRCALPHA)surface.fill((0, 0, 0))rotated_surface = surfacerect = surface.get_rect()ax = int(screen_width / 2)ay = int(screen_height / 2)angle = 0print("Size of the screen ({}, {})".format(screen_width, screen_height))print("Center of the screen ({}, {})".format(ax, ay))myfont = pygame.font.SysFont("monospace", 12)pygame.display.set_caption("Test rotate")main_loop = Trueamplifier = 200def calculate_angle(mouse_position):    dx = mouse_position[0] - ax    dy = mouse_position[1] - ay    return np.arctan2(dy,dx)while main_loop:    for event in pygame.event.get():        keys = pygame.key.get_pressed()        if event.type == pygame.QUIT or keys[pygame.K_ESCAPE]:            main_loop = False    pos = pygame.mouse.get_pos()    angle = (calculate_angle(pos) * 180)/math.pi    screen.fill((255,255,255))    rotated_surface = pygame.transform.rotate(surface, -angle)    rect = rotated_surface.get_rect(center = (ax, ay))    screen.blit(rotated_surface, (rect.x, rect.y))    pygame.draw.line(rotated_surface, WHITE, (ax,ay), (ax+20, ay), 1)    pygame.draw.line(rotated_surface, WHITE, (ax+10,ay-10), (ax+20, ay), 1)    pygame.draw.line(rotated_surface, WHITE, (ax+10,ay+10), (ax+20, ay), 1)    pygame.display.update()    CLOCK.tick(30)pygame.quit()我正在繪制一個(gè)箭頭并希望根據(jù)鼠標(biāo)在屏幕上的位置旋轉(zhuǎn)它。我當(dāng)然可以在每次進(jìn)行一些正弦、余弦計(jì)算時(shí)重新繪制線條，但這很痛苦。我認(rèn)為表面可以在這里幫助我，事實(shí)上，它適用于完美旋轉(zhuǎn)的矩形。但是將我的線條畫到表面上是行不通的。所以，我想我誤解了表面的用途，或者我編碼錯(cuò)誤，有更好的方法來做到這一點(diǎn)。請(qǐng)注意，如果我在我的 draw.line 指令中用 screen 替換了 Rodated_surface，箭頭確實(shí)會(huì)在屏幕上繪制，但永遠(yuǎn)不會(huì)旋轉(zhuǎn)。有什么想法（除了使用圖像/精靈；））？