我正在嘗試做這樣的事情：我的輸入：predefined_list=['gross pay']predefined_dict={'a':'o','o':'a','g':'c','c':'g'}想要的output: ['gross pay', 'gross poy', 'grass pay', 'crass pay', cross pay, crass poy] 以及其他幾種組合。我試過了：predefined_list=['gross pay']predefined_dict={'a':'o','o':'a','g':'c','c':'g'}i=0;for key,value in predefined_dict.items(): final=predefined_list[i].replace(key,value) i+=1 if final not in predefined_list: predefined_list.append(final)print(predefined_list)
2 回答
瀟湘沐
TA貢獻1816條經(jīng)驗 獲得超6個贊
試試這個方法
for key, value in predefined_dict.items():
for word in predefined_list:
for n in range(word.count(key)):
final = word.replace(key,value,n+1)
if final not in predefined_list:
predefined_list.append(final)
輸出：
>>> predefined_list
['gross pay', 'gross poy', 'grass pay', 'grass poy', 'cross pay', 'cross poy', 'crass pay', 'crass poy']
翻閱古今
TA貢獻1780條經(jīng)驗 獲得超5個贊
只需通過遍歷字典的鍵和值來替換字符串
modified_list = [predefined_list[0].replace(k,v) for k,v in predefined_dict.items()]
輸出
['gross poy', 'grass pay', 'cross pay', 'gross pay']
相似地
predefined_list = ['pay gross', 'gross pay']
modified_dict = {list_k: [list_k.replace(k,v) for k,v in predefined_dict.items()]
for list_k in predefined_list}
輸出
{'gross pay': ['gross poy', 'grass pay', 'cross pay', 'gross pay'],
'pay gross': ['poy gross', 'pay grass', 'pay cross', 'pay gross']}
添加回答
舉報
0/150
提交
取消