似乎“復(fù)雜”( getC) 函數(shù)被阻塞了。我假設(shè)通道一旦被讀取就會(huì)被銷毀，因此我想知道如何sC與getC函數(shù)和main函數(shù)共享通道而不會(huì)陷入死鎖（當(dāng)前片段）package mainfunc main() {//simple function and complex function/channel    sC := make(chan string)    go getS(sC)    cC := make(chan string)    go getC(sC, cC)//collect the functions result         s := <-sC//do something with `s`. We print but we may want to use it in a `func(s)`print(s)//after a while we do soemthing with `c`        c := <-cC    print(c)}func getS(sC chan string) {    s :=  " simple completed "    sC <- s}func getC(sC chan string, cC chan string) {//we do some complex stuff  print("complex is not complicated\n")//Now  we need the simple value so we try wait for the s channel.    s := <-sC    c := s + " more "    cC <- c //send complex value}