我試圖在我的網(wǎng)絡(luò)服務(wù)中反序列化一個(gè) post 請求,但我最終得到一個(gè) HTTP 500 說javax.json.bind.JsonbException: Error deserialize JSON value into type: class [C. 我正在使用 Jackson 來處理 JSON 內(nèi)容。這是我從 Postman 發(fā)送的 JSON 字符串:{"firstName":"FirstName","middleName":"middleName","lastName":"LastName","name":"SomeName","password":"$0meR@nd0m","creationTimeStamp":1533950475466} 這是我的 POJO :@XmlRootElementpublic class UserFormInterceptor { @Pattern(regexp = "^[\\S][\\p{L} .'-]+$") @Size(min = 2, max = 64) @NotEmpty @NotNull private String firstName; @Pattern(regexp = "^[\\S][\\p{L} .'-]+$") @Size(min = 2, max = 64) private String middleName; @Pattern(regexp = "^[\\S][\\p{L} .'-]+$") @Size(min = 2, max = 64) @NotEmpty @NotNull private String lastName; @Pattern(regexp = "^[a-zA-z][\\w]*$") @Size(min = 8, max = 64) @NotEmpty @NotNull private String name; @Pattern(regexp = "(?=.*?[A-Z]+)(?=.*?[0-9]+)(?=.*?[\\p{Punct}]+).*") @Size(min = 8, max = 64) @NotEmpty @NotNull private char[] password; @Positive @NotEmpty @NotNull private long creationTimeStamp; public UserFormInterceptor() {} public UserFormInterceptor(@NotNull String name, @NotNull String password, @Positive long creationTimeStamp, @NotNull String firstName, String middleName, @NotNull String lastName) { this.name = name; this.password = password.toCharArray(); this.creationTimeStamp = creationTimeStamp; this.firstName = firstName; this.middleName = middleName; this.lastName = lastName; } @NotNull public String getFirstName() { return firstName; } public void setFirstName(@NotNull String firstName) { this.firstName = firstName; } public String getMiddleName() { return middleName; } public void setMiddleName(String middleName) { this.middleName = middleName; } @NotNull public String getLastName() { return lastName; } public void setLastName(@NotNull String lastName) { this.lastName = lastName; }
添加回答
舉報(bào)
0/150
提交
取消