我想根據(jù)這樣的要求存儲元素列表：循環(huán)列表并檢查每個字符串如果是這個字符串，則將除當(dāng)前字符串之外的其他字符串存儲在列表中。a = ["I","have","something","to","buy"]當(dāng)循環(huán)到“I”或“have”或“something”或“buy”時，除當(dāng)前循環(huán)的元素外，其他元素將存儲在列表中。例如，我們循環(huán)到“something”，因此將存儲“I”、“have”、“to”、“buy”。我的代碼：store = []for x in a: if x: #I stuck here, I am really sorry, I know I should give more example, #but I really cant continue after here.我的預(yù)期輸出：[["have","something","to","buy"], ["I","something","to","buy"], ["I","have","to","buy"], ["I","have","something","buy"], ["I","have","something","to"]]
3 回答
繁花如伊
TA貢獻(xiàn)2012條經(jīng)驗 獲得超12個贊
a = ["I","have","something","to","buy"]
store = []
for x in a:
s = []
for i in a:
if i == x:
continue
else:
s.append(i)
store.append(s)
print(store)
試試這個
藍(lán)山帝景
TA貢獻(xiàn)1843條經(jīng)驗 獲得超7個贊
由于您只檢查列表中已有的單詞，因此您可以將問題簡化為：
wordLists = [a[:w]+a[w+1:] for w in range(len(a))]
輸出：
[['have', 'something', 'to', 'buy'], ['I', 'something', 'to', 'buy'], ['I', 'have', 'to', 'buy'], ['I', 'have', 'something', 'buy'], ['I', 'have', 'something', 'to']]
慕工程0101907
TA貢獻(xiàn)1887條經(jīng)驗 獲得超5個贊
您實際上是在從 5 個元素的列表中尋找 4 個元素（沒有替換）的所有組合。
使用itertools.combinations：
from itertools import combinations
a = ["I", "have", "something", "to", "buy"]
print(list(combinations(a, 4)))
# [('I', 'have', 'something', 'to'), ('I', 'have', 'something', 'buy'),
# ('I', 'have', 'to', 'buy'), ('I', 'something', 'to', 'buy'),
# ('have', 'something', 'to', 'buy')]
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