我在嘗試實(shí)現(xiàn)這個(gè)時(shí)遇到了一個(gè)問題（所有 goroutine 都睡著了 - 死鎖！）這是代碼的要點(diǎn)：var workers = runtime.NumCPU()func main() {    jobs := make(chan *myStruct, workers)    done := make(chan *myStruct, workers)    go produceWork(file_with_jobs, jobs)    for i := 0; i < runtime.NumCPU(); i++ {        go Worker(jobs, done)    }    consumeWork(done)}func produceWork(vf string, jobs chan *utils.DigSigEntries) {    defer close(jobs)    // load file with jobs    file, err := ini.LoadFile(vf)    // get data for processing    for data, _ := range file {        // ...        jobs <- &myStruct{data1, data2, data3, false}    }}func Worker(in, out chan *myStruct) {    for {        item, open := <-in        if !open {            break        }        process(item)        out <- item    }    // close(out)   --> tried closing the out channel, but then not all items are processed    //                  though no panics occur.}func process(item *myStruct) {    //...modify the item    item.status = true}func consumeWork(done chan *myStruct) {    for val := range done {        if !val.status {            fmt.Println(val)        }    }}我主要是想了解如何在不使用同步/等待的東西的情況下做到這一點(diǎn) - 只是純粹的渠道 - 這可能嗎？此例程的目標(biāo)是讓單個(gè)生產(chǎn)者加載由 N 個(gè)工人處理的項(xiàng)目 - 感謝任何指示/幫助。