我正在練習(xí)一個問題：鍵入多個數(shù)字并在鍵入 0 時(shí)停止。打印出您鍵入的數(shù)字的最大值、最小值和平均值。以下是我的代碼，我被困在平均值的計(jì)算中。例如：當(dāng)我輸入：2 5 7 -1 0 結(jié)果是：Type some numbers, and type 0 to end the calculattion: 2 5 7 -1 0The numbers you type are: 2 5 7 -1 Sum is: 13There are 4 numbersThe Max number is : 7The minimum number is : -1Average is : 3.0但是，平均值應(yīng)為 3.25。我已經(jīng)將變量 avg 設(shè)為 double 類型，為什么我的輸出仍然是 3.0 而不是 3.25？謝謝?。ublic class Max_Min_Avg {public static void main(String[] args) {    System.out.println("Type some numbers, and type 0 to end the calculattion: ");    Scanner scanner = new Scanner(System.in);    int numbs = scanner.nextInt();    int count =0;    int sum =0;    int max = 0;    int min=0;    System.out.println("The numbers you type are: ");    while(numbs!=0) {        System.out.print(numbs + " ");        sum += numbs;        count ++;        numbs = scanner.nextInt();        if(numbs>max) {            max = numbs;        }        if(numbs<min) {            min = numbs;        }    }    while(numbs ==0) {        break;    }    System.out.println();    double avg = (sum/count);    System.out.println("Sum is: "+ sum);    System.out.println("There are "+ count + " numbers");    System.out.println("The Max number is : " + max );    System.out.println("The minimum number is : " + min);    System.out.println("Average is : " + avg);}